Answer:
you can identify an unknown substance by measuring its density and comparing your results to a list of known densities. Density=mass/volume. Assume that you have to identify an unknown metal. You can determine the mass of the metal on a scale.
Answer:
The answer you have selected is correct
Explanation:
Answer:
The answer to your question is below
Explanation:
1)
Balanced chemical reaction
2CH₃OH + 3O₂ ⇒ 2 CO₂ + 4H₂O
Reactant Element Product
2 C 2
8 H 8
8 O 8
Molar mass of CH₃OH = 2[12 + 16 + 4]
= 2[32]
= 64 g
Molar mass of O₂ = 3[16 x 2] = 96 g
Theoretical proportion CH₃OH/O₂ = 64 g/96g = 0.67
Experimental proportion CH₃OH/O₂ = 60/48 = 1.25
Conclusion
The limiting reactant is O₂ because the Experimental proportion was higher than the theoretical proportion
2)
Balanced chemical reaction
S₈ + 12O₂ ⇒ 8SO₃
Reactant Elements Products
8 S 8
24 O 24
Molar mass of S₈ = 32 x 8 = 256 g
Molar mass of O₂ = 12 x 32 = 384 g
Theoretical proportion S₈ / O₂ = 256 / 384
= 0.67
Experimental proportion S₈ / O₂ = 40 / 35
= 1.14
Conclusion
The limiting reactant is O₂ because the experimental proportion was lower than the theoretical proportion.
Given:
Concentration 1 = 100.0 ml Concentration 2 = ?
Volume 1 = 0.100 M KCL Volume 2= 0.500 M KCL
Find Concentration 2
To get the concentration 2, follow this formula
C1V1 = C2V2
Solution
(100.0 ml) (0.100 m kcl) = (X ml) (0.500 m kcl)
transfer the volume 2 to the left side
(100.0 ml) (0.100 m kcl) = X ml
---------------------------------
0.500 m kcl
10.00ml / m kcl = Xml
-------------------- cancel the m kcl to let the ml be the remaining variable
0.500 m kcl
20.0 ml = x ml
So you will need 20.0 ml of 0.500 m kcl to made the solution of 100.0 ml of 0.100 m kcl
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