I NEED HELP ASAP!!<br> I DOMT KNOW HOW TO DO THIS

What is the process in which alkene monomers join end-to-end, or add on to one another, to form chains?

Thepotemich [5.8K]

ALKENES LIKE ETHYLENE JOIN END TO END TO FORM POLYETHYLENE BY ADDITION POLYMERIZATION TO FORM A LONG CHAIN SINCE THEY ARE UNSATURATED.
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8 0

3 years ago

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Troyanec [42]

Answer: Hope This Helps

Explanation:

1: The nephrons contain a filter called the glomerulus. The fluid that is filtered from the blood then travels down through a tubule. The tubule adjusts the level of wastes that will leave the body in the urine.

(I dont know the second part so hope this half answer helps a little bit. Sorry.)

8 0

3 years ago

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Can you please help me and can you show your work please

natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

$1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O$

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

$1.2mol*\frac{40.00g}{1mol} =41.2g$

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

$45g*\frac{1mol}{180.15g}=0.25g$

4. Here, since the molar mass of ammonia is 17.03 g/mol:

$20mol*\frac{17.03g}{1mol}=340.6g$

5. Here, since the molar mass of SO2 is 64.06 g/mol:

$48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules$

Best regards!

5 0

3 years ago

Calculate the standard molar enthalpy of formation, in kJ/mol, of NO(g) from the following data:

Paraphin [41]

The above question is incomplete, here is the complete question:

Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:

$N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o = 66.4 kJ$

$2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o= -114.1 kJ$

Answer:

The standard molar enthalpy of formation of NO is 90.25 kJ/mol.

Explanation:

$N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o_{1} = 66.4 kJ$

$2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o_{2} = -114.1 kJ$

To calculate the standard molar enthalpy of formation

$N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?$ ...[3]

Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[1] - [2] = [3]

$N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?$

$\Delta H^o_{3} =\Delta H^o_{1} - \Delta H^o_{2}$

$\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ$

According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :

= $\frac{\Delta H^o_{3}}{2 mol}$

$=\frac{180.5 kJ}{2 mol}=90.25 kJ/mol$

3 0

3 years ago

1. What type of wave is shown below?

svlad2 [7]

Answer : The correct option is, transverse wave.

Explanation :

Longitudinal waves : It is defined as the waves in which the particles of the medium move in the direction of the wave.

Transverse wave : It is defined as the waves in which the particles of the medium travel perpendicularly to the direction of the wave.

Surface wave : It is defined as a combination of transverse and longitudinal waves.

From the given image we conclude that, this illustration depict the transverse wave because the particles of the medium move perpendicularly to the direction of the wave.

Hence, the type of wave is, transverse wave

3 0

4 years ago

I NEED HELP ASAP!! I DOMT KNOW HOW TO DO THIS