The molecular weight of SOCL2 is 118.97 g/mol
1)
Lets take 100g of this compound.
It contains
50.05 g S and 49.95 g O.
2)
M(S) = 32.06 g/mol
M(O) = 16.00 g/mol
50.05 g S*1mol S/32.06 g S= 1.56 mol S
49.95 g O*1mol O/16.00 g O =3.12 mol O
3) S:O =
=1.56 mol S : 3.12 mol O = (1.56 mol /1.56 mol ) : (3.12 mol /1.56 mol) =1:2
(mol S):(mol O)=1 : 2
SO2
Answer:
Explanation:
Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)
Mass of uncreystaliized product = 109.03 gm - 105.98 gm
Mass of uncrystaliized product = 3.05 gm
For methyl benzoate;
mass = 3.08 g
no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole
It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.
moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles
∴
mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol
mass of nitro methyl benzoate = 4.098 gm
For HNO_3 solution:
mass = 1.42 gm/ml × 2.0 ml
mass = 2.84 gm
Mass of HNO3 in 2.84 gm solution
= 1.9596 gm
Moles of HNO3 =
= 0.0311 mole
1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate
Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole
The mass for nitro methyl benzoate can now be determined as:
= 0.0311 mole × 181.5 gm/mole
= 5.634 gm
Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.
The mass obtainable from the LR = 4.098 gm
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▹ Answer
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▹ Step-by-Step Explanation
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<u>Calculate</u>
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Hope this helps!
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Brainliest is greatly appreciated!
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Idk but ithink is F
idk ijust think