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sleet_krkn [62]

3 years ago

11

I am a fraction that is greater than 1 but less than 2 the sum of my numerator and denominator is 11 my denominator subtracted f

rom my numerator is 1 what fraction am I

1 answer:

maxonik [38]3 years ago

6 0

Answer:

that fraction is an improper fraction I think.

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Sam needs 7 1/2 cups of orange juice to make punch for a group of her friends. She only has 5 1/3 cups. Write and solve an equat

Solnce55 [7]

Answer:

Equation is $x+\frac{16}{3}=\frac{15}{2}$ where $x$ denotes number of cups of orange juice needed by Sam.

$x=\frac{13}{6}$

Step-by-step explanation:

Let $x$ denotes number of cups of orange juice needed by Sam.

Number of cups needed to make punch $=7\frac{1}{2} =\frac{15}{2}$

Number of cups with Sam $=5\frac{1}{3}=\frac{16}{3}$

Therefore,

$x+\frac{16}{3}=\frac{15}{2}\\\\x= \frac{15}{2}-\frac{16}{3}\\\\x=\frac{45-32}{6}\\\\x=\frac{13}{6}$

4 0

2 years ago

What formula do i use when it tells me to find the area with a given circumference? If you know please give an example as well,

liberstina [14]

Answer:

Step-by-step explanation:

A = C^2 / 4 x pi

so if the circumfernce was 10 you would square it to make it 100 and then you would do 4 x pi to get 12.57 ( rounded).

you would then just divide 100 by 12.57 = 7.96 ( rounded)

hope it helped

6 0

2 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

2 years ago

Sean is helping his dad build a tiled walkway in their backyard. The walkway will be 69 feet long and 2 feet wide. The local har

Flura [38]

First we should figure out how many times 2 goes into 69,(because each tile is 2 feet long) and I am going to do that by dividing 69 by 2. I got 34.5, so we can just say 35 to make it easier. So we now know we need 35 tiles, but they come in boxes of 6, so we will need to divide 35 by 6. It didn't make a full number (it was 5.833) but we need a full number of tiles so we will round up.

Our final number of how many boxes of tiles is 6.

6 0

2 years ago

Read 2 more answers

If f(x)=2x Write g(x) (the equation) if g(x) is f(x) translated 2 units down and then reflected over the x-axis.

Vedmedyk [2.9K]

F(x) = 2x ⇒ g(x) = -f(x) - 2 = -2x - 2

⇒ g(x) = -2 × (x + 1)

7 0

3 years ago