Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.
![\begin{tabular} {|c|c|c|c|c|c|} &Frequently&Occassionally&Not at all&Total\\[1ex] Male&227&454&798&1,479\\ Female &205&450&747&1,402\\ Total&432&904&1,545&2,881 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0A%20%26Frequently%26Occassionally%26Not%20at%20all%26Total%5C%5C%5B1ex%5D%0AMale%26227%26454%26798%261%2C479%5C%5C%0AFemale%20%26205%26450%26747%261%2C402%5C%5C%0ATotal%26432%26904%261%2C545%262%2C881%0A%5Cend%7Btabular%7D)
Part A:
If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

Part B:
If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

Part C:
If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

Part D:
If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

Part E:
The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.
Indeed from the table, there are 205 females who are frequently involved in charity work.
Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
If you triple the ginger, to be able to keep proportion, you would need triple the nutmeg as well.
The answer is 16, you substitute the value of the variable into the equation and simplify
A three digit number would be 294. You could do 200+90+4
Answer:
5 feet of wall should be on each side of the painting.
Step-by-step explanation:
Given that a 3 foot wide painting should be centered on 13 foot wide wall, to determine how many feet should be on each side of the painting, the following calculations must be performed:
(13 - 3) / 2 = X
10/2 = X
5 = X
Therefore, 5 feet of wall should be on each side of the painting.