Answer
given.
Mass of big fish = 15 Kg
speed of big fish = 1.10 m/s
mass of the small fish = 4.50 Kg
speed of the fish after eating small fish =?
a) using conservation of momentum
m₁v₁ + m₂v₂ = (m₁+m₂) V
15 x 1.10 + 4.50 x 0 = (15 + 4.5)V
16.5 = 19.5 V
V = 0.846 m/s
b) Kinetic energy before collision
KE₁ = 9.075 J
Kinetic energy after collision
KE₂ = 6.98 J
Change in KE = 6.98 - 9.075 = -2.096 J
hence,
mechanical energy was dissipated during this meal = -2.096 J
Answer:
m = 0.59 kg.
Explanation:
First, we need to find the relation between the frequency and mass on a spring.
The Hooke's law states that
And Newton's Second Law also states that
Combining two equations yields
The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.
And given that ω = 2πf
the relation between frequency and mass becomes
.
Let's apply this to the variables in the question.
Answer:
Explanation:
The given time is 1 / 4 of the time period
So Time period of oscillation.
= 4 x .4 =1.6 s
When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum
velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .
So required velocity is the maximum velocity of the block while remaining in contact with the spring.
v ( max ) = w A = 1.32 m /s.
Answer:
The answer is B
Explanation:
5/2=2.5
2.5x2=5
Hope this helps ik its kinda confusing lol
