Answer:
4.5m/s
Explanation:
Linear speed (v) = 42.5m/s
Distance(x) = 16.5m
θ= 49.0 rad
radius (r) = 3.67 cm
= 0.0367m
The time taken to travel = t
Recall that speed = distance / time
Time = distance / speed
t = x/v
t = 16.5/42.5
t = 0.4 secs
tangential velocity is proportional to the radius and angular velocity ω
Vt = rω
Angular velocity (ω) = θ/t
ω = 49/0.4
ω = 122.5 rad/s
Vt = rω
Vt = 0.0367 * 122.5
Vt =4.5 m/s
Answer:
Explanation:
radius of gyration of wheel k then
k² = r²/2
r² = 2 k²
r = √2 k
= 1.414 x .3 m
r = .4242 m
Moment of inertia of wheel
= mass x radius of gyration ²
= 25 x .3 x .3
= 2.25 kg m²
Friction force acting on it ( sliding )
= μmg , μ being coefficient of kinetic friction
This friction force will create linear acceleration in forward direction
Acceleration produced
= μg
= .6 x 9.8
= 5.88 m / s ²
This will also rotate the wheel , angular acceleration being
linear acceleration / radius
= 5.88 /.4242
= 13.86 radian / s²
Answer:
inductance of the coil 29.3767 H
Explanation:
given data
resistor R = 19.0 kΩ = 19 × 10³ Ω
potential applied V = 50.0 V
current I = 2.20 mA = 2.20 × 
A
time t = 2.80 ms = 2.80 × s
solution
we know for maximum current in circuit that is
current = V ÷ R .........1
current = 
current = 2.63 × A
so at time t = 0
t = 
L = 29.3767
