Answer:
Time period, T = 403.78 years
Explanation:
It is given that,
Orbital distance, ![a=1\ AU=1.496\times 10^{11}\ m](https://tex.z-dn.net/?f=a%3D1%5C%20AU%3D1.496%5Ctimes%2010%5E%7B11%7D%5C%20m)
Mass of the Earth, ![m_e=5.972\times 10^{24}\ kg](https://tex.z-dn.net/?f=m_e%3D5.972%5Ctimes%2010%5E%7B24%7D%5C%20kg)
Mass of the planet, ![m_p=2m_e=11.944\times 10^{24}\ kg](https://tex.z-dn.net/?f=m_p%3D2m_e%3D11.944%5Ctimes%2010%5E%7B24%7D%5C%20kg)
Let T is the orbital period of this planet. The Kepler's third law of motion gives the relation between the orbital period and the orbital distance.
![T^2=\dfrac{4\pi^2}{Gm_p}a^3](https://tex.z-dn.net/?f=T%5E2%3D%5Cdfrac%7B4%5Cpi%5E2%7D%7BGm_p%7Da%5E3)
![T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 11.944\times 10^{24}}\times (1.496\times 10^{11})^3](https://tex.z-dn.net/?f=T%5E2%3D%5Cdfrac%7B4%5Cpi%5E2%7D%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%2011.944%5Ctimes%2010%5E%7B24%7D%7D%5Ctimes%20%281.496%5Ctimes%2010%5E%7B11%7D%29%5E3)
![T=1.28\times 10^{10}\ s](https://tex.z-dn.net/?f=T%3D1.28%5Ctimes%2010%5E%7B10%7D%5C%20s)
or
T = 403.78 years
So, the orbital period of this planet is 404 years. Hence, this is the required solution.
Your answer would be 94. This is because only 10 transfers, so 90 is lost from the mouse. It takes 4 for the cat to pounce. When you add 90 and 4 you get your answer.....94
Okay my dude...
It is best to end up your relationship with Heaven.
You can already know from the description you put to her compared to Kye.
So it is better to have someone who knows how to love you than someone that knows how to forget you.
And also, does Kye know that you have another lover? 0 - 0
+1
An electron has a negative charge so losing a charge of -1 from an uncharged, or neutral, atom will leave an ion with a positive charge.
Answer:
After a crime scene has been discovered, measures must be taken to secure and protect the scene from contamination. To maintain the integrity of the scene, law enforcement must take action to block off the surrounding area as well as keep track of who comes in and goes out.