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3 years ago

What are two ways that convention currents in the ocean distribute the suns energy?

Physics

1 answer:

PtichkaEL [24]3 years ago

3 0

Answer:

The Sun dumps a lot of thermal energy by sunlight into the atmosphere, and especially into the oceans. Basically, currents arise as warm equatorial waters move to the NORTH carrying heat, and as part of this flow, the cold polar waters go south and there get heated.

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Please help 50 points given not cap

wariber [46]

1) false 2) false 3) true

5 0

3 years ago

The period of a simple pendulum, defined as the time necessary for one complete oscillation, is measured in time units and is gi

Iteru [2.4K]

Answer:

Explanation:

T = 2π √l/g

The dimension for l = m

The dimension for g = m/s²

The dimension for 2π is nothing. Since it's a constant, it is dimensionless.

Now we proceed ahead. Since we are not using the 2π, for the sake of this proving, our formula will temporarily be written as

T = √l/g

Inputting the dimensions, we have

T = √(m) / (m/s²)

T = √(m * s²/m)

T = √s²

T = s

Since the unit of period itself is in s, we can adjudge that the equation is dimensionally constant.

4 0

3 years ago

The major intracellular positively charged electrolyte is

lianna [129]

the answer is potassium.

4 0

3 years ago

On the way to the moon, the Apollo astronauts reach a point where the Moon’s gravitational pull is stronger than that of Earth’s

Mariana [72]

Answer:

3.456 × 10^(8) m

Explanation:

We are given;

Mass of earth; m_e = 5.98 × 10^(24) kg

Mass of moon; m_m = 7.36 × 10^(22) kg

Distance from earth to moon; L = 3.84 × 10^(8) m.

We are told that the Moon’s gravitational pull is stronger than that of Earth’s.

Thus;

F_EA ≤ F_MA

Formula for force due to gravity is;

F = GMm/r²

Applying to this question, we have;

(Gm_e•m_a)/x² ≤ (Gm_m•m_a)/(l - x)²

Where x is his distance from the center of the Earth

Now, G and m_a will cancel out from both sides and we plug on other values to get;

(5.98 × 10^(24))/x² ≤ (7.36 × 10^(22))/(3.84 × 10^(8) - x)²

Taking square root of both sides gives;

2445403852127.4966/x ≤ 271293199325.0107/(3.84 × 10^(8) - x)

Rearranging gives;

2445403852127.4966(3.84 × 10^(8) - x) ≤ 271293199325.0107x

Simplifying this gives;

9.0139(3.84 × 10^(8) - x) ≤ x

(34.613 × 10^(8)) - 9.0139x ≤ x

(34.613 × 10^(8)) ≤ x + 9.0139x

(34.613 × 10^(8)) ≤ 10.0139x

x ≥ (34.613 × 10^(8))/10.0139

x ≥ 3.456 × 10^(8)

5 0

3 years ago

A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The blo

erik [133]

The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d

The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.

Therefore,

using Newtons third law

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m × $\frac{v}{\frac{d}{v} }$

F- f = m × v²/d

Therefore,

F- f = mv² / d

8 0

2 years ago