Answer:
f1 = -3.50 m
Explanation:
For a nearsighted person an object at infinity must be made to appear to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.
∴ v = -3.5 m
Using mirror formula,
i/f1 = 1/v + 1/u
Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u = object distance = at infinity(∞) = 1/0
∴ 1/f1 = (1/-3.5) + 1/infinity
Note that, 1/infinity = 1/(1/0) = 0/1 =0.
∴ 1/f1 = 1/(-3.5) + 0
1/f1 = 1/(-3.5)
Solving the equation by finding the inverse of both side of the equation.
∴ f1 = -3.50 m
Therefore a converging lens of focal length f1 = -3.50 m
would be needed by the person to see an object at infinity clearly
V=f*lambda .. so make lambda the subject.. Lambda is equal to V/ F ... the answer is 6.66*10^3. I converted km to meters
Answer:
<em>Its true</em> i think
Explanation:
Answer:
the statement that best compares potential and kinetic energy would be only kinetic energy increases when velocity of an object increases
Explanation:
Answer:
force=1250kg * 30m/s+10
Explanation: it's a change in acceleration