Please Help (IF YOU CAN) Me With These Geometry Questions

Mathematics

1 answer:

Blizzard [7]3 years ago

5 0

Draw the line OB. It's another radius of the circle, just like OC, so it's 17. Now look at DB. It's 15, because a radius that's perpendicular to a chord bisects the chord. So we have the triangle ODB. It's a right triangle. The hypotenuse is 17, one leg is 15, and we have to find the other leg.
Dr. Pythagoras tells us exactly how. (One leg squared) + (the other leg squared) = (the hypotenuse squared). It's really tough trying to type math here on my phone, so I'll let you go ahead and finish up the last step.

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Angles U and V are supplementary angles. The ratio of their measures is 7:13 Find the measure of each angle

GREYUIT [131]

If $u$ and $v$ are supplementary angles, then

$u+v=180^{\circ}~~~~~\mathbf{(i)}$

The ratio of $u$ and $v$ is $\dfrac{7}{13}:$ 

$\dfrac{u}{v}=\dfrac{7}{13}\\\\\\ u=\dfrac{7v}{13}~~~~\mathbf{(ii)}$

Substitute $\mathbf{(ii)}$ into $\mathbf{(i)}:$

$\dfrac{7v}{13}+v=180^{\circ}\\\\\\ \left(\dfrac{7}{13}+1 \right )\cdot v=180^{\circ}\\\\\\ \left(\dfrac{7}{13}+\dfrac{13}{13} \right )\cdot v=180^{\circ}\\\\\\ \dfrac{20}{13}\cdot v=180^{\circ}\\\\\\ v=180^{\circ}\cdot \dfrac{13}{20}\\\\\\ \boxed{\begin{array}{c} v=117^{\circ} \end{array}}$

From $\mathbf{(i)},$ we find the measure of $u:$

$u=180^{\circ}-v\\\\ u=180^{\circ}-117^{\circ}\\\\ \boxed{\begin{array}{c} u=63^{\circ} \end{array}}$

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Lera25 [3.4K]

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Step-by-step explanation:

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Please help me If 180°<α<270°, cos⁡ α=−8/17, what is sin -α?

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