Find the area of a parallelogram with the given vertices. P(–5, –2), Q(7, –2), R(–2, 8), S(10, 8)

Mathematics

1 answer:

beks73 [17]3 years ago

4 0

Area of a parallelogram = bh

First, find b (base):

b = 12

Then find h (height):

h = 10

Multiply:

120

The answer is D) 120 units^2

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a function is defined on the complex numbers by where and are positive numbers. this function has the property that for each com

dedylja [7]

The value of p+q = 403,For the given complex number a+bi and $b^{2} =\frac{p}{q}$

where p and q are co-primes

F(z)= (a+ib)z⇒this is equidistant from "0" and "z"

Given modulus of complex number (a+ib) = 10 ; $b^{2} =\frac{p}{q}$ p and q ∈Z

G.C.D of ( p and q)=1

(a+ib)z equidistant from "0" and "z"

$&\Rightarrow|(a+i b) z-z|=|(a+i b) \bar{z}-0|\\&|z(a+i b-1)|=|(a+i b) \bar{z}|\\&[\bar{z}||(a-1)+i b|=| z|(a+i b)|\\&|a-1+i b|=|a+i b|\\&\sqrt{(a-1)^2+b^2}=\sqrt{a^2+b^2}\\&|a+i b|=10 \quad a^2+1-2 a+b^2=x^2+b^2\\&\sqrt{a^2+b^2}=10\\&a=1 / 2\\&a^2+b^2=100\\&b^2=100-\frac{1}{4}\\$

$b^{2} =\frac{399}{4}$

p = 399 and q= 4

p+q= 399+4

p+q=403

Hence the value of p+q = 403

Complete question:A function f is defined on the complex number by f (z) = (a + bi)z, where 'a' and 'b' are positive numbers. This function has the property that the image of each point in the complex plane is equidistant from that point and the origin. Given that |a+bi|=8 and that $b^{2} =\frac{p}{q}$ where p and q are coprime. Find the value of (p+q)

Learn more about complex numbers here:

brainly.com/question/20566728

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1 year ago

Complete the table below?

siniylev [52]

ABC = $425

Load = 0

Total Cost = $425

Sales Price = $850

Sales price ÷ total cost = 850/425