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2 years ago

What is being displayed ?

Mathematics

1 answer:

sleet_krkn [62]2 years ago

4 0

Answer: The answer is (2)

Just evaluate the functions with the values of the figure

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23 x 32 is the prime factorization for which one of these choices?

antoniya [11.8K]

<h2>Answer:</h2>

⟶ 2³ × 3² is the prime factorization for which one of these choices?

Let's check,

1) 6 = 3 × 2 [So, obviously not this choice]

2) 25 = 5 × 5 = 5² [Not this either]

3) 36 = 3 × 2 × 2 × 3 = 3² × 2² [Doesn't match with 2³ × 3²]

4) 72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3² [Matches]

⟶ The answer is, choice 72.

$\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}$

3 0

2 years ago

Find the solution of ___ and determine if it is an extraneous solution

Alex

Answer:

x = 14 is an extraneous solution

Step-by-step explanation:

$4\sqrt{x + 2} = -16$

Divide both sides by 4.

$\sqrt{x + 2} = -4$

Square both sides.

$(\sqrt{x + 2})^2 = (-4)^2$

$x + 2 = 16$

$x = 14$

Since we squared both sides, we much check for extraneous solutions because the process of squaring both sides can introduce extraneous solutions.

Check x = 14:

$4\sqrt{x + 2} = -16$

$4\sqrt{14 + 2} = -16$

$4\sqrt{16} = -16$

$4(4) = -16$

$16 = -16$

16 = -16 is a false statement, so the solution we found, x = 14, is an extraneous solution.

6 0

3 years ago

Factorise x² - 7x +10

Dafna1 [17]

(x-2) (x-5)
Lmk if you need step by step

5 0

3 years ago

What does this equal to

konstantin123 [22]

660/5.5 is 120. This is the answer.

4 0

3 years ago

If √5+√2=a+b√10 find a and b

Liono4ka [1.6K]

Answer:

Firstly, we'll apply the below identity.

${\boxed{\sf{(a+b)^{2} = a^{2} + b^{2} +2ab}}}$

Applying the above identity.

⇒ (√5 + √2)²

⇒ (√5)² + (√2)² + 2×(√5)×(√2)

⇒ 5 + 2 + 2√10

⇒ 7 + 2√10

Comparing the LHS and RHS

⇒ 7 + 2√10 = a + b√10

∴ a = 7 and b = 2.

4 0

1 year ago