3 years ago

Approximate the real zeros of x^4-5x^3+6x^2-x-2 to the nearest tenth. a. 0.4, c. 4, 3.4 b. , 3.4 d. -4, 3.4

Mathematics

1 answer:

sertanlavr [38]3 years ago

5 0

The zeroes are -0.4 and 3.4

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Step-by-step explanation:

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Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)

vlabodo [156]

We know that $\log_a(bc)=\log_a(b)+\log_a(c)$ .

Using this rule,

$\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)$ .

We also know that $\log_c(a^b)=b\log_c(a)$ .

Using this rule,

$\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)$

Now we know that $\log_c(A)=2,\log_c(B)=5$ so,

$5\cdot2+3\cdot5=10+15=\boxed{25}$ .

Hope this helps :)

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