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Nata [24]
3 years ago
15

Anna earns $9 an hour babysitting. She wants to buy a 16 GB iPad that is $120. Anna has saved $45 so far. How many more hours of

babysitting does she need to do to earn the rest to purchase the iPad?
Mathematics
2 answers:
natta225 [31]3 years ago
8 0
Its 8.33 but go ahead and put 9
lord [1]3 years ago
6 0
\dfrac{\$ 120 - \$45 }{ \$9\ \text{per hr}} = \dfrac{25}{3}\ \text{hr}

That's 8 hours 20 minutes to make the $75 more she needs.



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Who can help me and answer the 2 questions for me :(
Art [367]
For Question 1:
angle CAB, angle ABC, angle BCA

Question 2: angle BCD
8 0
3 years ago
Jason's two test scores in English are 87 and 91. What must he score on the third test to get an average test score of 92 or bet
irga5000 [103]

You first find the average of the first two test scores. When you find the average, you add the two numbers together and then divide by two which gives you 89. You then plug in different scores above the number 89 and find the average of those (89 and x) to see which gives you an average of 92. It’s mostly a guess and check type of problem.

5 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
WHOEVER ANSWERS FIRST GETS BRAINLIEST AND 100 POINTS <br> 0.1*√20000<br> -0.05*√28800
____ [38]

Answer:

0.1*√20000 = 14.1421356237

-0.05*√28800 = -8.48528137424

Step-by-step explanation:

8 0
3 years ago
Rewrite the following as like fractions (having the same denominator) and place them in order from least to greatest.
Maksim231197 [3]
2/3, 5/6, 4/7....common denominator is 42
2/3 = 28/42
5/6 = 35/42
4/7 = 24/42
least to greatest : 2/3, 5/6, 4/7

3/4, 7/12, 4/5....common denominator is 60
3/4 = 45/60
7/12 = 35/60
4/5 = 48/60
least to greatest : 7/12, 3/4, 4/5

7/10, 8/15, 11/20.....common denominator is 60
7/10 = 42/60
8/15 = 32/60
11/20 = 33/60
least to greatest : 8/15, 11/20, 7/10


3 0
3 years ago
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