A sample liquid is cooled to 150 degree Celsius to 30 degree Celsius, causing the liquid to change into a solid. which of the fo
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Answer : The volume of chloramphenicol stock solution needed is, 0.4 mL
Explanation :
First we have to calculate the mass of chloramphenicol.
As, the mass of chloramphenicol in 1 mL of solution =
So, the mass of chloramphenicol in 400 mL of solution =
Thus, the mass of chloramphenicol is, 0.01 g
Now we have to calculate the volume of chloramphenicol stock solution needed.
Concentration of chloramphenicol =
As, of chloramphenicol needed 1 mL volume of chloramphenicol stock solution
So, of chloramphenicol needed
volume of chloramphenicol stock solution
Thus, the volume of chloramphenicol stock solution needed is, 0.4 mL
Answer:
49.1 g
Explanation:
First we <u>convert 9.67x10²³ atoms of oxygen into moles</u>, using <em>Avogadro's number</em>:
- 9.67x10²³ atoms ÷ 6.023x10²³ atoms/mol = 1.60 mol O
Then we <u>calculate how many P₃O₉ moles there would be with 1.60 O moles</u>:
- 1.60 mol O *
= 0.18 mol P₃O₉
Finally we convert 0.18 P₃O₉ moles into grams, using its molar mass:
- 0.18 mol P₃O₉ * 237 g/mol = 49.1 g
Answer:
Explanation:
Given:
Depth = h
Width = w
Length = 1
Now,
Let ρ be the density of water
Thus,
Pressure force at the bottom will be
= Pressure × Area
= ρgh × (w × 1)
also,
Pressure force at the sides will be =
ρgh × (h × w)
Therefore,
The ratio of the pressure force at the bottom to the pressure force on the side of the tank will be
=
=