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jeyben [28]
2 years ago
14

Which property of gases allows them to be stored at high concentrations in a bottle of air freshener?

Chemistry
2 answers:
lorasvet [3.4K]2 years ago
7 0
Compressibility, i think..
steposvetlana [31]2 years ago
6 0
<h3><u>Answer;</u></h3>

Compressibility

<u>Compressibility</u> is the property of gases that allow them to be stored at high concentrations in a bottle of air freshener.

<h3><u>Explanation;</u></h3>
  • Gases possess various characteristics which includes; they are easy to compress, occupy more space than liquids and solids, and also they expand to fill their containers.
  • <em><u>Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles. This allows gas particles  to move freely to fit into the gaps of space between them. </u></em>
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Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f
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<em>K</em> = 5.0 × 10^25

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<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

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The relation between <em>E</em>° and <em>K</em> is

<em>E</em>° = (<em>RT</em>)/(<em>nF</em>)ln<em>K </em>

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<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

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