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AleksAgata [21]
3 years ago
11

The rectangle below has an area of X squared -144 m² and a length of X +12 m what expression represents the width of the triangl

e
Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0
A = L* W
W = A / L
W = (x^2-144m^2)/(x+12m)
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AaBbCc x AaBbCc (use for all 3 questions) 1. What is the probability that this individual will: AABBcc 2. What is the probabilit
tankabanditka [31]

Answer: 1. P = 1/64

             2. P = 1/32

             3. P = 1/8

Step-by-step explanation:

In genetics, an ofspring inherits one copy of an allele of each parent, which can be described in the tables below called Punnett Square:

For crossing Aa x Aa:

       A      a

A    AA   Aa

a    Aa    aa

For crossing Bb x Bb:

        B      b

B     BB    Bb

b     Bb    bb

For crossing Cc x Cc:

       C      c

C    CC    Cc

c     Cc     cc

We can separate them because they are assorted independently.

For offspring with <u>genotype</u> <u>AABBcc</u>, probability will be:

P(AA) = 1/4

P(BB) = 1/4

P(cc) = 1/4

As all three probabilities has to happen at the same time, it is a "E" rule:

P(AABBcc) = (\frac{1}{4}) (\frac{1}{4}) (\frac{1}{4})

P(AABBcc) = 1/64

Probability for the individual to be AABBcc is 1/64 or 1.56%.

<u>Genotype</u> <u>AaBBcc</u>:

P(Aa) = 2/4 = 1/2

P(BB) = 1/4

P(cc) = 1/4

P(AaBBcc) = (\frac{1}{2}) (\frac{1}{4}) (\frac{1}{4})

P(AaBBcc) = 1/32

Probability for the individual to be AaBBcc is 1/32 or 3.12%

<u>Genotype</u> <u>AaBbCc</u>:

P(Aa) = 1/2

P(Bb) = 1/2

P(Cc) = 1/2

P(AaBbCc) = (\frac{1}{2}) (\frac{1}{2}) (\frac{1}{2})

P(AaBbCc) = 1/8

Probability for the individual to be AaBbCc is 1/8 or 12.5%.

4 0
3 years ago
In 1906, the famous escape artist, Houdini, jumped into the San Francisco Bay with a metal ball chained to
lawyer [7]
The ball weighed 75 pounds, Houdini weighed 150 pounds
4 0
4 years ago
3. Solve:
Leto [7]

Answer: A

Step-by-step explanation:

Take 2 equations that make one of their letters disappear, and add them up:

2x + y + z = 1

 x - y + 4z = 0

------------------------

3x + 5z = 1

Do the same with another 2 equations in which the letter, in this case y, can be removed. If you can't, take 2 of 3 equations and equal the value of the letter to make it eliminable.

x - y + 4z = 0

x + 2y - 2z = 3

Since we can't eliminate y, we have multiply as necessary to make it eliminable:

2 (x - y + 4z = 0)

= 2x - 2y + 8z = 0

add all up:

2x - 2y + 8z = 0

 x + 2y - 2z = 3

-----------------------------

3x + 6z = 3

Now we've gone from a 3-variable equation to a 2-variable equation.

3x + 5z = 1

3x + 6z = 3

We can solve again by elimination; to get rid of z, for example, we cross multiply. the upper equation by 6 and the lower equation by 5. However, we have to make one of them negative in order to make them eliminable.

6 (3x + 5z = 1)

-5 (3x + 6z = 3)

----------------------------

18x + 30z = 6

-15x - 30z = -15

---------------------------

3x = - 9

Solving for x;

x = \frac {-9}{3}

x = - 3

After finding one variable, we can use our 2-variable equations to find the next variable:

3x + 5z = 1

3 (-3) + 5z = 1

- 9 + 5z = 1

5z = 1 + 9

5z = 10

z = \frac{10}{5}

z = 2

Having found these 2 variables, we can put them into one of our main 3-variable equations to find the last one:

2x + y + z = 1

2(-3) + y + 2 = 1

- 6 + y + 2 = 1

y - 4 = 1

y = 1 + 4

y = 5

And you've found all the variables in the equation; to prove if they're correct or not, you can replace them in any of the main equations and the result should be equal to each other:

x + 2y - 2z = 3

-3 + 2(5) - 2(2) = 3

- 3 + 10 - 4 = 3

10 - 7 = 3

3 = 3

7 0
3 years ago
The amount of water an electric
nikdorinn [45]

Answer:

‍❤️‍‍

Step-by-step explanation:

6 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
Effectus [21]

Answer:

m = 25xd

Step-by-step explanation:

25 per day means multiplication.

first think of just one siberian tiger for d days. that would be 25d because 25 lbs each day.

similarly, one day but x tigers is 25x.

if you have both many tigers and many days, it is 25xd

5 0
3 years ago
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