Answer:
Part A
Time period, designated by the symbol, 'T', is defines as the time it takes for a complete cycle of an oscillation or vibration (of a wave) to transit through a given point.
The longer the time period of a wave, the lower the frequency of the wave
The unit of the time period is seconds, 's'
Part B
Mathematically, the formula for the time period is presented as follows;
f = 1/T
∴ T = 1/f
f = v/λ
∴ T = λ/v
Where;
v = The velocity of the wave;
λ = The wavelength of the wave
Explanation:
Answer:
1. battery is capable of continuous current, capacitor is not
2. battery maintains a potential, capacitor does not
3. battery stores chemical energy, capacitor stores electric energy
Explanation:
1. battery is capable of continuous current, capacitor is not
This is because the battery maintains a constant current throughout while the capacitor maintains an exponential decaying current.
2. battery maintains a potential, capacitor does not
This is because, the battery has a potential at its terminal due to its emf whereas, the capacitor needs a potential to be applied to its terminals.
3. battery stores chemical energy, capacitor stores electric energy
This is because, the battery converts chemical energy to electrical energy whereas, the capacitor stores electric energy due to its ability to store electric charge.
Answer:
(a) 6.283 Wb (b) 69.11 Wb (c) I = 0.628 A
Explanation:
Given that,
The diameter of the loop, d = 40 cm
Radius, r = 20 cm
Initial magnetic field, B = 5 mT
Final magnetic field, B' = 55 mT
Initial magnetic flux,

Final magnetic flux,

Due to change in magnetic field an emf will be generated in the loop. It is given by :

Let I be the current in the loop. We can find it using Ohm's law such that,

Hence, this is the required solution.
The total power emitted by an object via radiation is:

where:
A is the surface of the object (in our problem,


is the emissivity of the object (in our problem,

)

is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is

Substituting these values, we find the power emitted by radiation:

So, the correct answer is D.