1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zysi [14]
3 years ago
14

An astronaut finds herself in a predicament in which she has become untethered from her shuttle. She figures that she could get

back to her shuttle by throwing one of three objects she possesses in the opposite direction of the shuttle. The masses of the objects are 5.3 kg, 7.9 kg, and 10.5 kg, respectively. She is able to throw the first object with a speed of 15.00 m/s, the second with a speed of 11.2 m/s, and the third with a speed of 7.0 m/s. If the mass of the astronaut and her remaining gear is 75.0 kg, determine the final speed of the astronaut with respect to the shuttle if she were to throw each object successively, starting with the least massive and ending with the most massive. Assume that the speeds described are those measured in the rest frame of the astronaut.
Physics
1 answer:
Blizzard [7]3 years ago
7 0

In order to solve the problem, it is necessary to apply the concepts related to the conservation of momentum, especially when there is an impact or the throwing of an object.

The equation that defines the linear moment is given by

mV_i = (m-m_O)V_f - m_OV_O

where,

m=Total mass

m_O = Mass of Object

V_i = Velocity before throwing

V_f = Final Velocity

V_O = Velocity of Object

Our values are:

m_1=5.3kgm_2=7.9kg\\m_3=10.5kg\\m_A=75kg\\m_{Total}=m=98.7Kg

Solving to find the final speed, after throwing the object we have

V_f=\frac{mV_0+m_TV_O}{m-m_O}

We have three objects. For each object a launch is made so the final mass (denominator) will begin to be subtracted successively. In addition, during each new launch the initial speed will be given for each object thrown again.

That way during each section the equations should be modified depending on the previous one, let's start:

A) 5.3Kg\rightarrow 15m/s

V_{f1}=\frac{mV_0+m_TV_O}{m-m_O}

V_{f1}=\frac{(98.7)*0+5.3*15}{98.7-5.3}

V_{f1}=0.8511m/s

B) 7.9Kg\rightarrow 11.2m/s

V_{f2}=\frac{mV_{f1}+m_TV_O}{m-m_O}

V_{f2}=\frac{(98.7)(0.8511)+(7.9)(11.2)}{98.7-5.3-7.9}

V_{f2} = 2.0173m/s

C) 10.5Kg\rightarrow 7m/s

V_{f3}=\frac{mV_{f2}+m_TV_O}{m-m_O}

V_{f3}=\frac{(98.7)(2.0173)+(10.5)(7)}{98.7-5.3-7.9-10.5}

V_{f3} = 3.63478m/s

Therefore the final velocity of astronaut is 3.63m/s

You might be interested in
50 points!!! Kinetics
iris [78.8K]

Answer:

98 m √

Explanation:

How about s = Vo * t + ½at² ?

s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6

and

h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490

Subtract 2nd from first:

0 = -8Vo + 470.4

Vo = 58.8 m/s

h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m

3 0
2 years ago
Read 2 more answers
How do very high density objects appear in an ultrasound?
evablogger [386]
<span>Density is entirely unrelated to an object's size. It is a property of a given</span>
7 0
3 years ago
Why does a balloon filled with the air from your lungs sink to the ground but a balloon filled with Helium floats ?
hoa [83]

Helium is lighter than air from the lungs.

Explanation:

A balloon filled with the air from lungs will sink to the ground but a balloon filled with Helium floats because helium is lighter than air.

Air is a mixture of many gases.

The air from the lungs is predominantly made up of carbon dioxide and water vapor.

  • Gram per mole of carbon dioxide is 44. Water vapor is 18.
  • Compared to helium which is 4, we see that the gas is lighter.
  • Since the gas is lighter, it will float in air.
  • The main component of air around us is nitrogen gas with a gram per mole of 28.
  • A balloon filled with more of air from the lungs weigh more than that will filled air around and even far more than helium gas.
  • This will cause a helium filled balloon to float.

learn more:

Density brainly.com/question/1698555

#learnwithBrainly

4 0
3 years ago
The acquisition of electric charge without contact between charged and/or uncharged substances.
Lera25 [3.4K]

Answer:

induction

Explanation:

I just did usatestprep

4 0
3 years ago
Read 2 more answers
The y component of the electric field of an electromagnetic wave traveling in the +x direction through vacuum obeys the equation
Alexxx [7]

Answer: 8.6 µm

Explanation:

At a long distance from the source, the components (the electric and magnetic fields) of the electromagnetic waves, behave like plane waves, so the equation for the y component of the electric field obeys an equation like this one:

Ey =Emax cos (kx-ωt)

So, we can write the following equality:

ω= 2.2 1014 rad/sec

The angular frequency and the linear frequency are related as follows:

f = ω/ 2π= 2.2 1014 / 2π (rad/sec) / rad = 0.35 1014 1/sec

In an electromagnetic wave propagating through vacuum, the speed of the wave is just the speed of light, c.

The wavelength, speed and frequency, are related by this equation:

λ = c/f

λ = 3.108 m/s / 0.35. 1014 1/s = 8.6 µm.

7 0
3 years ago
Other questions:
  • Describe how switching the desk lamp on and off shows that light waves transfer energy
    6·2 answers
  • As a rough approximation, the human body may be considered to be a cylinder of length L=2.0m and circumference C=0.8m. (To simpl
    10·1 answer
  • Does a cell ever reach equilibrium
    13·2 answers
  • The method of heat transfer by which the sun energy reaches the earth is
    8·2 answers
  • Why is the sun renewable but oil is non renewable?
    15·1 answer
  • What happens to the air resistance on a car as it speeds up? A) decreases b)stays the same C)it changes direction of the car D)i
    7·1 answer
  • Heating food under a heat lamp is an example of heat transfer by
    7·1 answer
  • A holiday ornament in the shape of a hollow sphere with mass 0.015 kg and radius 0.055 m is hung from a tree limb by a small loo
    7·1 answer
  • Ifa truck starts from rest and it has acceleration of 4 m/s for 5 second
    8·1 answer
  • The amount of force needed to keep a 0.1 kg basketball moving at a constant speed of 6 m/s on frictionless ice is how much N?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!