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rjkz [21]
3 years ago
15

Can science answer every question

Physics
2 answers:
Alla [95]3 years ago
5 0
No because your opinion and beliefs answers many questions
Roman55 [17]3 years ago
3 0
No because everyone will have a different opinion or belief , which will make every problem in science different
You might be interested in
Layers of Earth's Atmosphere
Tamiku [17]

Answer:

going to work my way down

Troposphere

contains weather

contains life forms

stratosphere

contains ozone layer

mesosphere

where asteroids burn up

very low temps

thermosphere

widely varying temps

exosphere

almost no molecules

Explanation:

3 0
4 years ago
3. The velocity of sound is 332 m/s. Answer the following questions:
Angelina_Jolie [31]

Answer:

20 Hz, 20000 Hz

0.0166 m, 16.6 m

Explanation:

The minimum frequency that a human ear can hear is 20 Hz

The maximum frequency that a human ear can hear is 20000 Hz.

v = Velocity of sound = 332 m/s

Wavelength is given by

\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}

The longest wavelength that can be heard by the human ear is 16.6 m

\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}

The shortest wavelength that can be heard by the human ear is 0.0166 m.

3 0
3 years ago
A 3kg book falls from a shelf. If it lands with a speed of 4.8 m/s, from what height did it fall? A. 28.8 m , B. 1.2 m , C. 0.6
Irina-Kira [14]
The correct answer is B. 1.2 m (apex)
7 0
3 years ago
Plz help me !!!!!!!!!!
ivolga24 [154]

Answer:

A. These vibrations can travel through solids, liquids, and gases, but not through <u>empty</u><u> </u><u>space</u>.

3 0
3 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
Bingel [31]

Answer:

given,

speed of the car = 20 m/s

final speed of car = 0 m/s

distance between car and the deer = 38 m

reaction time, t = 0.5 s

deceleration of the car = 10 m/s².

a) distance between deer and car

  distance travel in the reaction time

   d₁ = v x t

   d₁ = 20 x 0.5 = 10 m

   distance travel after you apply brake

   using equation of motion

   v² = u² + 2 a s

   0 = 20² - 2 x 10 x s

    s =  20 m

total distance traveled by the car

D = d₁ + d₂

D = 20 + 10 = 30 m

  distance between car and the deer = 38 m - 30 m

                                                              = 8 m

b) now, maximum speed car.

   distance travel in reaction time

    d₁ = s x t

    d₁ = 0.5 V

distance left between them

   d₂ = 38 - d₁

   d₂ = 38 - 0.5 V

   distance travel after you apply brake

   using equation of motion

    v² = u² + 2 a d₂

    0 = (V)² - 2 x 10 x (38 - 0.5 V)

     V² + 10 V - 760 = 0

now, solving the quadratic equation

  x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

  V = \dfrac{-10\pm \sqrt{10^2-4(1)(-760)}}{2(1)}

         V = 23.01 , -33.01

rejecting the negative term.

hence, maximum speed of the car could be V = 23.01 m/s

 

7 0
3 years ago
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