Answer:
a,b,c,d,,f, g, j
Explanation:
e) equipotential lines are lines connecting points of equal potential
h) electric field inside the conductor is non-zero even when there is net movement of charge or non-zero current.
i) capacitors' plates are charged and an electric field exists between the plates.
A covalent bond is considered covalent
Answer:
a) v = 4.4 m/s
b) F = 400 N
Explanation:
a) ½kx² = ½mv²
v = √(kx²/m)
F = kx
v = √(Fx/m)
v = √(800(0.012) / 0.5) = √19.2 = 4.3817...
b) Fd = ½mv²
F = mv²/2d
F = 0.5(19.2) / (2(0.012) = 400 N
