Answer:
The friction coefficient's minimum value will be "0.173".
Explanation:
The given query seems to be incomplete. Below is the attached file of the complete question.
According to the question,
(a)
The net friction force's magnitude will be:
⇒
(b)
For m₃,
⇒
Or,
⇒
Answer:
zirconium
Explanation:
Given, Mass of AgBr(s) = 23.0052 g
Molar mass of AgBr(s) = 187.77 g/mol
The formula for the calculation of moles is shown below:
Thus,
The reaction taking place is:
From the reaction,
4 moles of AgBr is produced when 1 mole of undergoes reaction
1 mole of AgBr is produced when 1 / 4 mole of undergoes reaction
0.1225 mole of AgBr is produced when mole of
undergoes reaction
Moles of got reacted = 0.030625 moles
Mass of the sample taken = 12.5843 g
Let the molar mass of the metal = x g/mol
So, Molar mass of = x + 4 × 79.904 g/mol = 319.616 + x g/mol
Thus,
Solve for x,
we get, x = 91.2999 g/mol
<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>