The answer is 5.2π in² = 16.3 in²
The area (A) of the circle with radius r is: A = r²π
It is known:
π = 3.14
![d=6- \frac{50}{t^{2}+10 }](https://tex.z-dn.net/?f=d%3D6-%20%5Cfrac%7B50%7D%7Bt%5E%7B2%7D%2B10%20%7D%20)
![r = \frac{d}{2}= \frac{6- \frac{50}{t^{2}+10 }}{2}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bd%7D%7B2%7D%3D%20%5Cfrac%7B6-%20%5Cfrac%7B50%7D%7Bt%5E%7B2%7D%2B10%20%7D%7D%7B2%7D%20)
t = 5
⇒
![=\frac{ \frac{42-10}{7}}{2}=\frac{ \frac{32}{7}}{ \frac{2}{1} }= \frac{32}{7}* \frac{1}{2} = \frac{16}{7}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%20%5Cfrac%7B42-10%7D%7B7%7D%7D%7B2%7D%3D%5Cfrac%7B%20%5Cfrac%7B32%7D%7B7%7D%7D%7B%20%5Cfrac%7B2%7D%7B1%7D%20%7D%3D%20%5Cfrac%7B32%7D%7B7%7D%2A%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B16%7D%7B7%7D%20)
A = r²π = (16/7)²π = (2.28)²π = 5.2π = 5.2 · 3.14 = 16.3 in²
Answer:
Step-by-step explanation:
The relevant relations are ...
- an arc has the same measure as the central angle it subtends
- angles of a linear pair are supplementary (total 180°)
- an inscribed angle has half the measure of the arc it subtends
- the total of arcs of a circle is 360°; of a semicircle, 180°
__
arc CB has the measure of central angle COB: 64°
angle AOC is the supplement of angle COB: 180° -64° = 116°
arc AD is twice the measure of inscribed angle ABD: 2×13° = 26°
arc DFB is the supplement of arc AD: 180° -26° = 154°
angle CDB is half the measure of arc CB: 64°/2 = 32°
You are not able to solve the problem because there different integers
Answer: the 4 its hella easy
Step-by-step explanation:
3v+1=6v-8
1+8=6v-3v
9=3v
9/3=v
Plug 3 into the expression to solve and you get 10.