Answer:
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cells in the vegetal half of the embryo should be unpigmented those in the animal half and there should be heavily pigmented.
Explanation:
The Yolk molecules moving in the vegetal halves of the egg which is the case in most of the animals, slows down the cell division. These lesser division area or the zone demarcates the area to be vegetal pole and due to lesser cell division, it becomes unpigmented or less pigmented Based on the observation time and perspect with assuming no movement.
The pole opposite to the vegetal, is animal pole which with absence or less of yolk, gets more ability to divide and hence become more pigmented or heavily pigmented. This brings polarity to the egg and becomes telolecithal egg.
Answer:
pH = 3.215
Explanation:
From the given information;
Using the equation for the dilution of a stock solution:
Since moles of C5H5N = moles of HNO3
Then:
The reaction between C5H5NH and H2O is as follows:
⇄ 
Now, the next step is to draw out the I.C.E table.
⇄
I 0.06333 0 0
C - x x x
E 0.06333 -x x x
![K_a = \dfrac{[C_5H_5N][H_3O^+] }{[C_5H_5N^+H] } \\ \\ 5.8824 \times 10^{-6} = \dfrac{x^2}{0.06333 - x}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5BC_5H_5N%5D%5BH_3O%5E%2B%5D%20%7D%7B%5BC_5H_5N%5E%2BH%5D%20%7D%20%20%5C%5C%20%5C%5C%20%205.8824%20%5Ctimes%2010%5E%7B-6%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B0.06333%20-%20x%7D)
Assuming x < 0.06333
Then
![[H_3O^+] = x = 6.1035 \times 10^{-4} \ M \\ \\ pH = -log (6.1035 \times 10^{-4}) \\ \\ \mathbf{\\ pH = 3.215}](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%20%20x%20%3D%206.1035%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20M%20%20%5C%5C%20%5C%5C%20%20pH%20%3D%20-log%20%286.1035%20%5Ctimes%2010%5E%7B-4%7D%29%20%5C%5C%20%5C%5C%20%5Cmathbf%7B%5C%5C%20pH%20%3D%203.215%7D)
The answer is D,Nucleus I think
Insulin and glucagon, are both are secreted from islets of Langerhans at the pancreas<span />
