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denis-greek [22]
4 years ago
13

Which model of election configuration is the most accurate? The quantum mechanical atomic model The Rutherford atomic model The

Bohr atomic model O Plum pudding atomic model The quantum gravity atomic model
Chemistry
2 answers:
Natasha_Volkova [10]4 years ago
7 0

Answer:

Quantum mechanical atomic model.

Explanation:

The first model of electronic configuration was given by Bohr's model.

The most accurate model of electronic configuration is the quantum mechanical atomic model.

Bohr's model has various limitations:

1. It does not explain the Zeeman effect and stark effect.

2. It is not valid for multi-electron system.

3. Heisenberg uncertainty principle is not followed by this model

The quantum mechanical atomic model explains all the four quantum numbers for the electronic configuration of an atom in the periodic table.

The quantum mechanical atomic model considered the Heisenberg uncertainty principle.

Maksim231197 [3]4 years ago
7 0

Answer:

Quantum mechanical atomic model.

Explanation:

The atom model given by quantum mechanics is the most modern, precise and complex, based on the mathematical form of the atomic structure.

Quantum theory states that matter has properties associated with waves, which is why the atom model was based on this theory. The so-called “Uncertainty Principle” states that the electron has no exact position in the electrosphere, no definite speed and direction. This is why the Bohr atom, with electrons spinning in circular orbits, is surpassed by the quantum model.

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Answer:

2Zn + 2HCl = H2 + 2ZnCl

Explanation:

Zn is a metal, when metals have reaction with strong acid it will produce H2 gas and the metal's salt which is ZnCl.

Later on you just make the equation in balance.

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The movement of water across a membrane is termed
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Which statement best describes electrons?(1) They are positive subatomic particles and are found in the nucleus.(2) They are pos
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3 years ago
In the Mond process for the purification of nickel, carbon monoxide is reacted with heated nickel to produce Ni(CO)4, which is a
igor_vitrenko [27]

<u>Answer:</u> The equilibrium constant for this reaction is 1.068\times 10^{6}

<u>Explanation:</u>

The equation used to calculate standard Gibbs free change is of a reaction is:

\Delta G^o_{rxn}=\sum [n\times \Delta G^o_{(product)}]-\sum [n\times \Delta G^o_{(reactant)}]

For the given chemical reaction:

Ni(s)+4CO(g)\rightleftharpoons Ni(CO)_4(g)

The equation for the standard Gibbs free change of the above reaction is:

\Delta G^o_{rxn}=[(1\times \Delta G^o_{(Ni(CO)_4(g))})]-[(1\times \Delta G^o_{(Ni(s))})+(4\times \Delta G^o_{(CO(g))})]

We are given:

\Delta G^o_{(Ni(CO)_4(g))}=-587.4kJ/mol\\\Delta G^o_{(Ni(s))}=0kJ/mol\\\Delta G^o_{(CO(g))}=-137.3kJ/mol

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(1\times (-587.4))]-[(1\times (0))+(4\times (-137.3))]\\\\\Delta G^o_{rxn}=-38.2kJ/mol

To calculate the equilibrium constant (at 58°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = Standard Gibbs free energy = -38.2 kJ/mol = -38200 J/mol  (Conversion factor: 1 kJ = 1000 J )

R = Gas constant = 8.314 J/K mol

T = temperature = 58^oC=[273+58]K=331K

K_{eq} = equilibrium constant at 58°C = ?

Putting values in above equation, we get:

-38200J/mol=-(8.314J/Kmol)\times 331K\times \ln K_{eq}\\\\K_{eq}=e^{13.881}=1.068\times 10^{6}

Hence, the equilibrium constant for this reaction is 1.068\times 10^{6}

4 0
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5 0
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