1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alinara [238K]
3 years ago
15

Help it's due tomorrow!!!!

Mathematics
1 answer:
zepelin [54]3 years ago
5 0
8a^2 + 3a^2

11a^2 

since both have a^2 you only have to add the coefficients 
You might be interested in
Solve the equation : |x| - 6 = 4
wlad13 [49]

Answer:

x=10

Step-by-step explanation:

10-6 is equal to 4. The absolute value of 10 is 10. Therefore, x=10. Brainliest?

6 0
3 years ago
Nine students in Maddie's classroom are wearing red. There are
goblinko [34]

Answer:

She is correct because 30 percent of 30 is 9 or in other words if you multiply 30 by 30 percent you get 9.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
Help me please!!!!!!!
Daniel [21]
C.4 is the right answer
6 0
3 years ago
Ginny's earnings from her lemonade stand decreased by 18% from last week to this week Ginny used the following expression to
jolli1 [7]
100-18= 82

B is your answer
8 0
2 years ago
Other questions:
  • Can someone help me with this?
    5·1 answer
  • A shop is having a sale on T-shirts. If you buy the first T-shirt for $17, each additional T-shirt will cost $5. Which formula m
    11·1 answer
  • What number is 25 precent of 20?
    14·2 answers
  • 44/18 into a mixed number
    12·2 answers
  • 4 9 16 25 36 nth term of the quadratic sequence
    14·1 answer
  • 3. The directions on a seed packet say to plant the seeds 1 inches
    15·1 answer
  • I need to find x but I don't know how
    14·1 answer
  • Determine if the following vectors are orthogonal, parallel, or neither.
    14·1 answer
  • 30 points please help
    10·1 answer
  • A car company claimed that it improved the gas mileage of a particular model of car between 2011 and 2012. A consumer advocacy g
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!