All students in each grade
audience: <u>students</u> - counts for both boys and girls.
option (B) for teachers is irrevelant.
option (C) doesn't include girls.
option (D) doesn't include the entire school
Hence, option A is correct.
Sure this question comes with a set of answer choices.
Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.
Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant. This is, the equation has the form:
y = a(x + 4)(x - 2)
Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:
10 = a (6 + 4) (6 - 2)
Therefore, any of these equivalent equations can be solved to determine the value of a:
10 = a 6 + 40) (6 -2)
10 = a (10)(4)
10 = 40a
The greatest common factor is 2
We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.
With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.
<h2>Helloooo!!! Marie Here!!!</h2><h2 />
The answer is here:
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Hope This Helps! Have A GREAT Day!</h3>
