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slavikrds [6]
4 years ago
14

What components are needed in a expeirment

Chemistry
1 answer:
AnnyKZ [126]4 years ago
7 0
Independent and dependent variables and constants
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{Plz answer} Thank you!
Dafna11 [192]

The Answer to your question would be A

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An example of gaining potential energy
aleksandr82 [10.1K]

Answer:

An example for gaining potential energy would be: A glass bottle on the top of a high shelf would have more high potential energy than a glass bottle on the middle or bottom shelf because it has a long way or more farther to fall down or brake.

Explanation:

Remember Potential Energy is the restored energy of an object has.

I hope this helps you!

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3 years ago
A scientist uses an accelerator and high energy electrons to study the particles inside the protons of a helium atom. What parti
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<span>B. the He nucleus C.the He electrons D.the He quarks</span>
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4 years ago
a radio controlled airplane is moving at a velocity of 23 m/s. it accelerates to a velocity of 85 m/s in 9.3 seconds. what accel
tatuchka [14]

I will show you a method to find a velocity of anything:-


Find average velocity when acceleration is constant.

Set up an equation with position and time instead.

Find the distance between the start and end points.

Calculate the change in time.

Divide the total displacement by the total time.

Solve problems in two dimensions.

7 0
3 years ago
A radioactive isotope of potassium (k) has a half-life of 20 minutes. if a 43 gram sample of this isotope is allowed to decay fo
Ksenya-84 [330]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 43 g

m (final mass after time T) = ? (in g)

x (number of periods elapsed) = ?

P (Half-life) = 20 minutes

T (Elapsed time for sample reduction) = 80 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

80 = x*20

80 = 20\:x

20\:x = 80

x = \dfrac{80}{20}

\boxed{x = 4}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{43}{2^{4}}

m = \dfrac{43}{16}

\boxed{\boxed{m = 2.6875\:g}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

8 0
4 years ago
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