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ArbitrLikvidat [17]
3 years ago
13

What independent variables can be tested in this lab setup? (List at least 5)

Chemistry
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

I know 2

dependent

independent

Explanation:

sorry that's about it from me

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Mashutka [201]

Answer:

Can you please post a pictah.

Explanation:

3 0
3 years ago
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FOR 99 POINTS WILL MARK BRAINLIEST If a person has clogged arteries and high blood pressure, his or her doctor might recommend a
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7 0
3 years ago
1) How much energy would be required to melt 15.0 g of ice at 0°C?
DerKrebs [107]

Answer:

5010J

Explanation:

The following data were obtained from the question:

Mass (m) = 15g

Heat of fusion (ΔHf) = 334J/g

Heat required (Q) =..?

The heat energy required to melt the ice can be obtained as follow:

Q = m·ΔHf

Q = 15 x 334

Q = 5010J

Therefore, the heat energy required to melt the ice is 5010J.

8 0
3 years ago
Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained
Delicious77 [7]

Answer:

higher

Explanation:

If it contains a impurity that is insoluble it won't dissolve completely, the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

3 0
2 years ago
The reaction of 15 moles carbon with 30 moles O2 will
chubhunter [2.5K]

Answer:

15 moles.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

C+O_2\rightarrow CO_2

Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:

n_{CO_2}=15molC*\frac{1molCO_2}{1molC} \\\\n_{CO_2}=15molCO_2

Best regards.

8 0
3 years ago
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