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scoray [572]
3 years ago
11

Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Answer:

35.6\ units

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

A(7, 1), B(-6, 1), C(10, 6)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(7, 1), B(-6, 1)

substitute in the formula

d=\sqrt{(1-1)^{2}+(-6-7)^{2}}

d=\sqrt{(0)^{2}+(-13)^{2}}

dAB=13\ units

Find the distance BC

B(-6, 1), C(10, 6)

substitute in the formula

d=\sqrt{(6-1)^{2}+(10+6)^{2}}

d=\sqrt{(5)^{2}+(16)^{2}}

dBC=16.8\ units

Find the distance AC

A(7, 1), C(10, 6)

substitute in the formula

d=\sqrt{(6-1)^{2}+(10-7)^{2}}

d=\sqrt{(5)^{2}+(3)^{2}}

dAC=5.8\ units

Find the perimeter

P=dAB+dBC+dAC

P=13+16.8+5.8=35.6\ units


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Answer:

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Step-by-step explanation:

Given:

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Solution:

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rounding to nearest tenth we get.

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