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alexandr1967 [171]
3 years ago
11

What is the multiplicative inverse of the sum of 1/3 + 1/5 ? Express in simplest form

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0
\frac{8}{15}

My Work/Reasoning:
First we find the sum of 1/3 and 1/5. \frac{1}{3} + \frac{1}{5} = \frac{5}{15} + \frac{3}{15} = \frac{8}{15}
Then, we find the multiplicative inverse, I guess it's also known as the reciprocal. \frac{8}{15} turns into \frac{15}{8}
Finally, we simplify. \frac{15}{8}=1 \frac{7}{8}
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The effective rate is calculated in the following way:
r =  {(1 +  \frac{i}{n} )}^{n} - 1
where r is the effective annual rate, i the interest rate, and n the number of compounding periods per year (for example, 12 for monthly compounding).
our compounding period is 2 since the bank pays us semiannually(two times per year) and our interest rate is 8%
so lets plug in numbers:
r = {(1 +  \frac{8\%}{2}) }^{2}  - 1 \\ r =  {(1 +  \frac{1}{25}) }^{2}  - 1 \\ r =  \frac{676}{625}  - 1 \\ r = 0.0816 \: or \: 8.16\%
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Find the area of the rectangle with a length of (x^2-2) and a width of (2x^2-x+2)
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Area=legnth times width

so multiply them together use distributive property
a(b+c)=ab+ac so
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so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
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Answer:

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