Answer:
daaang thats hard
<h2>wow :/</h2>
Step-by-step explanation:
Answer:
55°
Step-by-step explanation:
Given that;
Lines CD and DE are tangent to circle A and intersect at point D.
and:
Arc CE measures 125 degrees. Point B lies on circle A.
There lies a diagrammatic representation below given a clear picture of what this question looks like;
If arc CE is 125°, what is the measure of ∠CDE?
SO, by using the outside angle theorem
∠CDE = 
where arc CE = 125°
we can determine CBE by subtracting it from angle of a circle = 360°
Thus, CBE = 360° - 125°
CBE = 235°
Again; ∠CDE = 
∠CDE = 
∠CDE = 
∠CDE = 55°
∴ The measure of ∠CDE = 55°
Answer: 4). A = (b1 + b2)h/2
5).
A = (b x h)/2
6). A = b x h
7). A = b x h = 65 x 50 = 3250 ft^2
8). A = (b x h)/2 = (12 x 18)/2 = 108 inches^2
9). A = (b1 + b2)h/2 = (15 + 7)4/2 = 44m^2
Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s