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nadezda [96]
4 years ago
7

Describe the shapes and relative energies of the SPD & f atomic orbitals

Chemistry
1 answer:
Deffense [45]4 years ago
6 0

Explanation:

The shapes and relative energies of the orbitals s,p,d and f orbitals are given by the principal quantum number and the azimuthal quantum number.

The principal quantum number gives the main energy level and the azimuthal quantum number denotes the shape of the orbitals.

  • For the principal quantum number, they represent the energy levels in which the orbital is located or the average distance of the orbital from the nucleus. It takes the number n = 1,2,3,4,5,6,7......
  • The azimuthal quantum number(L) shows the shape of the orbitals in subshells accommodating electrons. The number of possible shapes is limited by the the principal quantum number.

L             Name of orbital                     shape of orbital

0                     s                                         spherical

1                      p                                         dumb-bell

2                     d                                        double dumb-bell

3                      f                                          complex

Principal                        Azimuthal                   Orbital

Quantum                       Quantum                    Designation of

Number (N)                  Number(l)                     Sublevel

       1                                   0                                   1s

       2                                  0                                   2s

                                            1                                   2p

       3                                  0                                   3s

                                            1                                    3p

                                            2                                   3d

      4                                   0                                    4s

                                           1                                      4p

                                           2                                      4d

                                           3                                      4f

Learn more:

Atomic orbitals brainly.com/question/9514863

#learnwithBrainly

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What would you multiply "grams of barium" by to get the units "moles of barium" ?
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What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
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Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

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We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

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We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

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Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

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Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

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The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

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