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KonstantinChe [14]

3 years ago

7

Copper is plated on zinc by immersing a piece of zinc into a solution containing copper(II) ions. In the plating reaction, coppe

r II ions: a) gain two electrons and is are reduced. b) lose two electrons and is are oxidized. c) gain two electrons and is are oxidized. d)lose two electrons and is are reduced.

1 answer:

Aloiza [94]3 years ago

8 0

Hey there!:

Copper plating on Zinc will occur via this simple reaction:

Cu²⁺ + 2 e⁻ ⇌ Cu

When a species gains electron, it is reduced. Its oxidation state is decreased. For example, in the above reaction Cu2+ gained 2 electron to get reduced to Cu. Its oxidation state changed from +2 to 0. Hence it is a reduction reaction.

So, the correct answer is :

The copper II ions gain two electrons and are reduced.

Answer B

Hope this helps!

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Partial pressure of the $PCl_5=p_3=217.0 Torr$

The expression of an equilibrium constant is given by :

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At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=p_1'=13.2 Torr$

Partial pressure of the $Cl_2=p_2'=?$

Partial pressure of the $PCl_5=p_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

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$p_2'=32.8 Torr$

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At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{p_3'}{p_1'\times p_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

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$p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

$p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

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