1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
7

Copper is plated on zinc by immersing a piece of zinc into a solution containing copper(II) ions. In the plating reaction, coppe

r II ions: a) gain two electrons and is are reduced. b) lose two electrons and is are oxidized. c) gain two electrons and is are oxidized. d)lose two electrons and is are reduced.
Chemistry
1 answer:
Aloiza [94]3 years ago
8 0

Hey there!:

Copper plating on Zinc will occur via this simple reaction:

Cu²⁺   +   2 e⁻   ⇌   Cu

When a species gains electron, it is reduced. Its oxidation state is decreased. For example, in the above reaction Cu2+ gained 2 electron to get reduced to Cu. Its oxidation state changed from +2 to 0. Hence it is a reduction reaction.

So, the correct answer is  :

The copper II ions  gain two electrons and are reduced.

Answer B

Hope this helps!

You might be interested in
Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +
nikklg [1K]

<u>Answer:</u>

<u>For 1:</u> The value of \Delta G for the chemical equation is -24.636 kJ/mol

<u>For 2:</u> The value of \Delta G for the chemical equation is -20.925 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)

  • <u>For 1:</u>

To calculate the \Delta G for given value of equilibrium constant, we use the relation:

\Delta G=-RT\ln K_p      .....(1)

where,

\Delta G = ? kJ/mol

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of \Delta G for the chemical equation is -24.636 kJ/mol

  • <u>For 2:</u>

The expression of K_p for the given chemical equation is:

K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}

We are given:

p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm

Putting values in above equation, we get:

K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52

Now, calculating the value of \Delta G by using equation 1:

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of \Delta G for the chemical equation is -20.925 kJ/mol

3 0
3 years ago
Read 2 more answers
What is known as the amount of<br> mass in a given volume?
Ganezh [65]

Answer:

Density

Explanation:

Density is a measure of how much mass is contained in a given volume

3 0
2 years ago
Need Answer ASAP. Scientists design drugs alongside which type of engineers? Structural, civil, chemical, aerospace
Scilla [17]

Answer:

Chemical

Explanation:

3 0
3 years ago
2 moles of substance A contains 12.04 × 1023 atoms.
professor190 [17]

Answer:

2 moles of Substance B

Explanation:

Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)

Therefore 12.04 × 10²³/ 6.02× 10²³  =  2 mole of Substance B

7 0
2 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
3 years ago
Other questions:
  • The molecule h2so4is ionized to h+ ions and so4- ions in water. would you predict this to result in a solution that is acidic or
    14·1 answer
  • How can you tell a Cu(No3)2 solution from a Ni(NO3)2 solution?
    10·1 answer
  • Rules for naming compounds are beneficial to the scientific community.
    10·2 answers
  • you are studying an element that is a gas at room temperature. Is it most likely a metal, nonmetal, or metalloid?
    7·2 answers
  • If 60.0 ml of a 1.5 m hcl solution is put into a flask and diluted with water to make 2.0 l of solution
    15·1 answer
  • M(8,7) is the midpoint of rs. The coordinates of s are (9,5) what is the coordinates of r
    7·1 answer
  • Granite is heterogeneous?
    12·2 answers
  • When a gun is recovered from a crime scene never touch the blank with hands or any other object so you don't accidentally discha
    5·2 answers
  • Consider two solutions separated by a semipermeable membrane, as shown in the illustration to the right. The membrane allows the
    8·1 answer
  • Write a balanced equation for the complete oxidation reaction that occurs when glucose (C6H12O6) reacts with oxygen. Use the sma
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!