Q= calories
m = mass
c = specific heat
∆t = temperature difference
Also, Qin = Qout
(as in the amount of energy lost by the iron equals the energy gained by water. the water) so the calories lost is as stated in pict.
A rigid tank contains water at 200kPa and an unknown temperature. When the tank is 100 °C the vapour starts condensing. Calculat
e the initial temperature of the water. Show the process on T-v diagram.
1 answer:
Answer:
T = 450 C
Explanation:
given,
pressure of rigid tank containing water = 200 kPa
water start condensing at 100 °C
vapor saturation pressure at 100 °C = 101421 Pa (from saturation table)
specific volume = 1.6718 m³/kg
From super heated steam table
steam table is two set of table which is of energy transfer properties of water and steam.
at v = 1.6718 m³/kg and pressure = 200 kPa
temperature is equal to T = 450 C
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Explanation:
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In other words, this law states a relation between the orbital period of a body (moon, planet, satellite) orbiting a greater body in space with the size
of its orbit.
This Law is originally expressed as follows:
(1)
Where;
is the Gravitational Constant and its value is
is the mass of Mars
is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
(2)
(3)
(4)
Finally:
This is the orbital period of a spacecraft in a low orbit near the surface of mars