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3 years ago

14

A charged particle is projected with its initial velocity parallel to a uniform magnetic field. What is the resulting path

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

<em>The particle will continue in a straight line parallel to the field</em>

Explanation:

If a charged particle moves parallel to a magnetic field, without cutting across the field, then there will be no force on the particle. Since there is no force on the charged particle from the magnetic field, its velocity will continue in its original path, which is parallel to the field.

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Dan is gliding on his skateboard at 4.00m/s . He suddenly jumps backward off the skateboard, kicking the skateboard forward at 6

frozen [14]

To solve this problem we will apply the concepts related to the conservation of the Momentum. For this purpose we will define the momentum as the product between mass and velocity, and by conservation the initial momentum will be equal to the final momentum. Mathematically this is,

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

Here,

$m_{1,2}$ = Mass of Dan and Skateboard respectively

$u_{1,2}$ = Initial velocity of Dan and Skateboard respectively

$v_{1,2}$ = Final velocity of Dan and Skateboard respectively

Our values are:

Dan's mass

$m_1 = 60kg$

Mass of the skateboard

$m_2 = 7.0kg$

Both have the same initial velocity, then

$u_1= u_2 = 4m/s$

Final velocity of Skateboard is

$v_2 = 6m/s$

Rearranging to find the final velocity of Dan we have then,

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

$m_1v_1+m_2v_2 = (m_1+m_2)u_1$

$v_1 = \frac{ (m_1+m_2)u_1 -m_2v_2}{m_1}$

Replacing,

$v_1 = \frac{(60+7)(4)-(7)(6)}{60}$

$v_1 = 3.76m/s$

Therefore Dan will touch the ground at a speed of 3.76m/s

5 0

4 years ago

A motor does 1000J of work in 18 seconds. What is the power of the<br> motor?

solong [7]

Answer:

55.56 watt

Explanation:

Work (W) = 1000 J

time (T) = 18 sec

power (P) = ?

We know power is the rate of doing work so

p = w / t

= 1000 / 18

= 55. 56 watt

7 0

3 years ago

You hold a metal block of mass 40 kg above your head at a height of 2 m.

Kitty [74]

Answer:

The work done by gravity is 784 J.

Explanation:

Given:

Mass of the block is, $m=40\ kg$

Height to which it is raised is, $h=2\ m$

Acceleration due to gravity is, $g=9.8\ m/s^2$

Now, work done by gravity is equal to the product of force of gravity and the distance moved in the direction of gravity. So,

$\textrm{Work by gravity}=F_g\times h$

Force of gravity is given as the product of mass and acceleration due to gravity.

$\therefore F_g=mg=40\times 9.8=392\ N$ . Now,

$\textrm{Work by gravity}=F_g\times h=392\times 2=784\ J$

Therefore, the work done by gravity is 784 J.

5 0

3 years ago

An electron moves on a circular orbit in a uniform magnetic field of 7.83×10-4 T. The kinetic energy of the electron is 55.3 eV.

yuradex [85]

Answer:

3.9E-8

Explanation:

We know that

Mv²/r = Bqv

So

r= mv/Bq

But E is 1/2mv² which is 5.53eV

m²v² =2m x 5.53eV

mv = √( 2 x 9.1E-31)

So

r= √( 2 x9.1E-31 x 5.53)/ 7.83x10^-4 x1.6E-19

= 3.9x10-8cm

Explanation:

7 0

3 years ago

A caterpillar travels straight for 3 cm, and then turns left and crawls 4 centimeters farther. If its final position is east of

Romashka-Z-Leto [24]

3-squared + 4-squared = 5-squared

The bug's displacement is 5cm east.

4 0

4 years ago

Read 2 more answers