Answer:
T= 5.18N
Explanation:
u = mass of chord / length of chord
u = 0.49/ 7.3
u = 0.067 kg/m
Velocity of sound waves (v) =length of chord / time taken for wave to travel
v = 7.3 / 0.83 = 8.795m/s
Tension is calculated below using the formula
T = v² * u
T = (8.795)² x 0.067
T= 5.18N
Answer:(10.69, 11.436)
Explanation:
Given
initial height of ball is 2 m
height of basket is 3.05 m
Launching angle

y=1.05
equation of trajectory of ball is given by

for x=12.27

u=10.69
for x=11.73

u=11.436 m/s
Thus range of speed is (10.69, 11.436)
Answer:
5.024 years
Explanation:
T1 = 1 year
r1 = 150 million km
r2 = 440 million km
let the period of asteroid orbit is T2.
Use Kepler's third law
T² ∝ r³
So,


T2 = 5.024 years
Thus, the period of the asteroid's orbit is 5.024 years.
Answer:
Change in momentum will be -4.4 kgm/sec
So option (A) is correct option
Explanation:
Mass of the ball is given m = 0.10 kg
Initial velocity of ball 
And velocity after rebound 
We have to find the change in momentum
So change in momentum is equal to
( here negative sign shows only direction )
So option (A) will be correct answer
Answer:
129.74 Hz
Explanation:
Given:
Wave velocity ( v ) = 346 m / sec
wavelength ( λ ) = 2.69 m
We have to calculate Frequency ( f ) :
We know:
v = λ / t [ f = 1 / t ]
v = λ f
= > f = v / λ
Putting values here we get:
= > f = 346 / 2.69 Hz
= > f = 34600 / 269 Hz
= > f = 129.74 Hz
Hence, frequency of sound is 129.74 Hz.