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3 years ago

6. An object moves along the x-axis. The graph shows its position x as a function of time t. Find

Physics

1 answer:

raketka [301]3 years ago

7 0

Answer: 1.5 m/s

Explanation:

9-3/5-1= 6/4= 3/2= 1.5

Used x2-x1/t2-t1 to get average velocity from point b to c

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What happen to the bulb when it is in series connection?

coldgirl [10]

If the bulb is in series with something else, then . . .

-- The brightness of the bulb depends on the other device in the circuit.

-- If the other device is designed to use less power than the bulb, then the
other device gets more power than the bulb gets.

-- If the other device is designed to use more power than the bulb, then the
other device gets less power than the bulb gets.

-- If the other device is removed from the circuit, then the bulb doesn't light at all.

This description of the often-screwy behavior of a series circuit may partly explain
why the electric service in your home is not a series circuit.

8 0

3 years ago

Read 2 more answers

How is velocity ratio of wheel and axle calculated

Rudiy27

Answer:

VR = $\frac{Radius of the wheel}{Radius of the axle}$

Explanation:

Velocity ratio (VR) of a machine is a term that compares the distance moved by effort put into the machine to the distance moved by the load.

A wheel and axle is a device for lifting of a load through a height. It is made up of two circular parts called wheel and axle. Its velocity ratio (VR) can be determined by:

VR = $\frac{Radius of the wheel}{Radius of the axle}$

For a practical wheel and axle, the diameter of the wheel is greater than the diameter of the axle.

7 0

3 years ago

A bicyclist is traveling at a speed of 20.0 m/s as he approaches the bottom of a hill. He decides to coast up the hill and stops

Rudiy27

Answer:

Vertical height of the hill, h = 20.4 meters

Explanation:

Given that,

Speed of the bicyclist, v = 20 m/s

To find,

The vertical height of the hill.

Solution,

Let h is the height of the hill. When he approaches the bottom of the hill, the loss in kinetic energy is equal to the gain in potential energy. Using the conservation of energy as,

$\dfrac{1}{2}mv^2=mgh$

$h=\dfrac{v^2}{2g}$

$h=\dfrac{(20)^2}{2\times 9.8}$

h = 20.4 meters

Therefore, the vertical height of the hill is 20.4 meters. Hence, this is the required solution.

5 0

3 years ago

A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10 m/s. The instan

gizmo_the_mogwai [7]

Answer:

The velocity just before hitting the ground is $v_f = 30 m/s$

Explanation:

From the question we are told that

The initial speed is $u = 10 m/s$

The final speed is $v = 30 \ m/s$

From the equations of motion we have that

$v^2 =u^2 + 2as$

Where s is the distance travelled which is the height of the cliff

So making it the subject of the the formula we have that

$s = \frac{v^2 - u^2 }{2a}$

Where a is the acceleration due to gravity with a value $a = 9.8m/s^2$

$s = \frac{30^2 - 10^2 }{2 * 9.8 }$

$s = 40.8 \ m$

Now we are told that was through horizontally with a speed of

$v_x =10 m/s$

Which implies that this would be its velocity horizontally through out the motion

Now it final velocity vertically can be mathematically evaluated as

$v_y = \sqrt{2as}$

Substituting values

$v_y = \sqrt{(2 * 9.8 * 40.8)}$

$v_y = 28.3 \ m/s$

The resultant final velocity is mathematically evaluated as

$v_f = \sqrt{v_x^2 + v_y^2}$

Substituting values

$v_f = \sqrt{10^2 + 28.3^2}$

$v_f = 30 m/s$

5 0

3 years ago

Gravitational energy can be negative?

AlladinOne [14]

answer:

yes

explanation:

At a separation of the surface of Earth (r=6400km) gravity wants pull the test mass closer and closer. ... So the work done by gravity is NEGATIVE. The gravitational potential energy is negative because us trying to do the opposite of what gravity wants needs positive energy.

6 0

3 years ago