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Katen [24]
1 year ago
7

Rewrite the following integral using the order of integration dydxdz​

Mathematics
1 answer:
Vlad [161]1 year ago
7 0

y is bounded between the plane y=z and the parabolic cylinder y=1-x^2. The other variables are bounded by constants, -1\le x\le1 and 0\le z\le1, so the integral is

\displaystyle \int_0^1 \int_{-1}^1 \int_z^{1-x^2} dy \, dx \, dz

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Find the equation of the line with slope of 4 and y-intercept of -3.
Lelechka [254]

Answer:

y = 4x -3

Step-by-step explanation:

The slope intercept form of an equation is

y = mx+b where m is the slope and b is the y ntercept

y = 4x -3

3 0
3 years ago
Simplify. look below
aliina [53]
I think the answer is C miss girl
3 0
3 years ago
?anybody know this need help prontoe
scoundrel [369]

Answer:

<P = 27°

Step-by-step explanation:

In a triangle, the sum of all three interior angles = 180

So triangle NOP, <N + <O + <P = 180

Plug in

9x - 1 + 3x - 2 + 2x + 1 = 180

14x = 2 = 180

14x = 182

x = 13

<P = 2x + 1

<P = 2(13) + 1

<P = 26 + 1

<P = 27

Answer:

<P = 27°

3 0
4 years ago
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Can someone help me with slope
inn [45]

Answer:

Yea sure.

Step-by-step explanation:

7 0
4 years ago
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Graph a line that contains the point (-5,-3) and has a slope of -2
nikitadnepr [17]

Given:

The line contains the point (-5,-3) and has a slope of -2.

To find:

The graph of the line.

Solution:

The line contains the point (-5,-3) and has a slope of -2. So, the equation of line is

y-y_1=m(x-x_1)

where, m is slope.

y-(-3)=-2(x-(-5))

y+3=-2(x+5)

y+3=-2x-10

Subtracting 3 from both sides, we get

y=-2x-10-3

y=-2x-13

So, the equation of line is y=-2x-13.

Putting x=0, we get

y=-2(0)-13

y=0-13

y=-13

It means, the line also passes through (0,-13).

Plot the points (0,-13) and (-5,-3) on a coordinate plane and connect them by a straight line.

Therefore, the graph of given line is shown below.

6 0
3 years ago
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