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eimsori [14]
4 years ago
10

Larry wants to buy some carpeting for his living room. The leangth of the room is 3 times the width and the total area of the ro

om is 12 square meters. what is the leangth of the living room ?
Mathematics
1 answer:
ioda4 years ago
5 0
Equation for length:
l = 3w

l × w = 12

Substitute 3w into L.
(3w) × w = 12
4w = 12
w = 3

Substitute 3 into w to find the length.
l = 3w
l = 3×3
l = 9

The width is 3 and the length is 9.
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Por un tubo de 2.5 cm de diámetro fluye agua con una repidez de 20 cm/s ¿Cuál es el valor del flujo y el gasto del agua?
kompoz [17]

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El flujo y gasto de agua es aproximadamente 98.175 centímetros cúbicos por segundo.

Step-by-step explanation:

El gasto del agua (Q), medido en centímetros cúbicos por segundo, es el flujo que pasa a través del tubo. La ecuación para determinar el gasto es:

Q = \frac{\pi}{4}\cdot D^{2}\cdot v (1)

Donde:

D - Diámetro del tubo, medido en centímetros.

v - Velocidad del flujo, medida en centímetros por segundo.

Si sabemos que D = 2.5\,cm y v = 20\,\frac{cm}{s}, entonces el flujo y gasto del agua es:

Q = \frac{\pi}{4}\cdot (2.5\,cm)^{2}\cdot \left(20\,\frac{cm}{s} \right)

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3 0
3 years ago
On what intervals is the graph of f(x)=x^3-2x^2+5x+1 increasing?
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f(x)=x^3-2x^2+5x+1\\ f'(x)=3x^2-4x+5\\
3x^2-4x+5=0\\\Delta=(-4)^2-4\cdot3\cdot5=16-60=-44
\Delta0 \Rightarrow the graph of the parabola is above the x-axis, so the derivative is always positive and therefore the initial function is increasing in its whole domain.

f(x)=0.5x^2-6\\
f'(x)=x
The function is decreasing when its first derivative is negative. The first derivative of this function is negative for x so for x\in(-\infty,0) the function is decreasing.

f(x)=\dfrac{x+1}{x-1}\qquad(x\not=1)\\
f'(x)=\dfrac{x-1-(x+1)}{(x-1)^2}=-\dfrac{2}{(x-1)^2}
The function is increasing when its first derivative is positive. The first derivative of this function is always negative therefore this function is never increasing.


3 0
4 years ago
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