Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer:
Step-by-step explanation:
- x² = 4² + (√34)²
- x² = 16 + 34
- x² = 50
- x = √50
- x = 5√2
18 = (240/100) x what;
what = 18 x (100/240);
what = 1800/240;
what = 7.5;
Answer:des
Step-by-step explanation:
