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Varvara68 [4.7K]
2 years ago
14

Karissa rides her bicycle for 4 hours and is 22 miles from her house. After riding for 8 hours, she is

Mathematics
1 answer:
inysia [295]2 years ago
8 0

Answer:

5.5

Step-by-step explanation:

We nned to divide to solve this!!

22/4 = 5.5

She is going 5.5 mph!!

Have an amazing day!!

Please rate and mark brainliest!!!!

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4x^2-21x-18=0<br> Find the discriminate
SpyIntel [72]

a = 4, b = -21, c = -18

to keep from getting "mixed up", evaluate the discriminant first ...

b<sup>2</sup> - 4ac = (-21)<sup>2</sup> - 4(4)(-18) = 729

sqrt(729) = 27

x = (21 +/- 27)/8

x = -3/4, x = 6

since the discriminant is a perfect square, the original quadratic will factor ...

4x<sup>2</sup> - 21x - 18 = 0

(4x + 3)(x - 6) = 0

x = -3/4, x = 6

6 0
3 years ago
Read 2 more answers
A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
I need help with one I don’t understand it
icang [17]
B is the answer hope this helps
4 0
3 years ago
Highest common factor of 24 and 108​
Angelina_Jolie [31]

Answer:

12

Step-by-step explanation:

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24  

The factors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108  

Then the greatest common factor is 12.

4 0
3 years ago
Read 2 more answers
The length of fencing required for a rectangular garden in terms of its width, x, if it’s length is 2 units more than 1.5 times
JulijaS [17]

Answer:

5x+4 units.

Step-by-step explanation:

Let x be the width of rectangle.

We have been given that the length of garden is 2 units more than 1.5 times it’s width. So length of the rectangle will be: 1.5x+2.

To find the length of total fencing we need to figure out perimeter of rectangle with width x and length 1.5x+2.

Since we know that perimeter of a rectangle is two times the sum of its length and width.

\text{Perimeter of rectangle}=2(\text{Length+Width})

Upon substituting length and width of garden in above formula we will get,

\text{Perimeter of rectangular garden}=2(1.5x+2+x)

\text{Perimeter of rectangular garden}=2(2.5x+2)

Upon using distributive property we will get,

\text{Perimeter of rectangular garden}=2*2.5x+2*2

\text{Perimeter of rectangular garden}=5x+4

Therefore, the length of required fencing will be 5x+4 units.

4 0
4 years ago
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