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Anton [14]
3 years ago
10

A top of a round cake has an area of about 201 square inches what is the circumference of the top of the cake rounded to the nea

rest inch
Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

we are given

A top of a round cake has an area of about 201 square inches

Let's assume radius of circle is 'r'

A=\pi r^2

now, we can plug values and solve for r

201=\pi r^2

r^2=\frac{201}{\pi}

r=8

now, we can find circumference

C=2\pi r

C=2\pi *8

C=50.2654 in

C=50in.................Answer



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nikitadnepr [17]

Answer:

A man borrows * 8000

He agrees to repay with a total interest of 1360 in 12 monthly instalments.

Each instalment being less than the preceding one by * 40

                                                                      =  \frac{12}{1360} x 40

                                                                      = 12 x 34

                                                                      = 408 (Ans)

                                                             

7 0
3 years ago
Write the sum of 5x2 + 2x - 10 and 2x2 + 6 as a polynomial in standard form.
vaieri [72.5K]

Answer:

7x^2+2x-4

Step-by-step explanation:

a standard form is ax+by=c

5x^2 add 2x^2=7x^2 then -2x but when you have a -10 +6 you get -4 giving you the answer of 7x^2 +2x -4

7 0
3 years ago
Read 2 more answers
a student reads at a rate of 16 pages per day which ordered pair would be on a graph of its relationship
mojhsa [17]
I found the choices that should have been included in this problem.
a) (1.5,26)
b) (2.25,30)
c) (5.5,88)
d) (7.25,110)

y = 16x
choice a. y = 16(1.5) = 24
choice b. y = 16(2.25) = 36
choice c. y = 16(5.5) = 88
choice d. y = 16(7.25) = 116

The correct answer is choice c. (5.5, 88)
8 0
3 years ago
© ABCD is a rectangle with sides 6 cm and
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Answer:

10

Step-by-step explanation:

If the sides of the rectangle is 6cm and 8cm, then we mean that, the length and breadth are 6cm and 8cm

The diagonal which cross at AX will be the hypotenus of the triangle formed by drawing the diagonal.

Hence,

Hypotenus = sqrt (opposite² + adjacent²)

AX = sqrt[(8²) + (6²)]

AX = sqrt(64 + 36)

AX = sqrt(100)

AX = 10

4 0
3 years ago
Solve for x. Show each step of the solution.<br> Show each step when solving for x.
andrew-mc [135]

-3x(4-6x) < x+5

-12x+18x² < x+5

-13x+18x² < 5

18x²-13x-5<0.

4 0
3 years ago
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