1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
spin [16.1K]
3 years ago
15

What principle of joint operations entails expending minimum essential combat power on secondary efforts in order to allocate th

e maximum possoble combat power on primary efforts?
Physics
1 answer:
iVinArrow [24]3 years ago
8 0
The principle of  joint operations that entails expending minimum essential combat power on secondary efforts in order to allocate the maximum possible combat power on primary efforts is called the economy of force. It is one of the principles of war that is based on Clausewitz's approach.  The economy of force is the principle where we employ all of the available combat power in a way that is the most effective as much as possible, attempting to allocate a least amount of important combat power to any efforts. It is closely associated to the idea of force concentration. According to this principle, any part of the whole effort should not be left idle.
You might be interested in
A proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton. Dete
gavmur [86]

Answer:

Electric field, E=10^{-7}\ N/C

Explanation:

It is given that, a proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton such that,

qE=mg

E=\dfrac{mg}{q}

E=\dfrac{1.67\times 10^{-27}\times 9.8}{1.6\times 10^{-19}}

E=1.02\times 10^{-7}\ N/C

or

E=10^{-7}\ N/C

So, the magnitude of electric field at the location of the proton is 10^{-7}\ N/C. Hence, this is the required solution.

8 0
4 years ago
A car traveling 75 km/h slows down at a constant 0.50 m/s2 just by "letting up on the gas." calculate (a) the distance the car c
Serjik [45]

Solution:

At 1st convert km/h to m/s. 1 km = 1000 m, 1 h = 3600 s, 1 km/m = 1000/3600 = 5/18 m/s  

Initial velocity = 75 * 5/18 = 20.8 m/s  

The car’s velocity decreases from 20.8 m/s to 0 m/s at the rate of 0.5 m/s each second. We have the final velocity, initial velocity, and the acceleration.  

Now according to the equation determine the distance.  

vf^2 = vi^2 + 2 * a * d  

a = -0.5 m/s^2  

0 = 20.8^2 + 2 * -0.5 * d  

so d = 431.64 m  

since we have the final velocity, initial velocity, and the acceleration. Use the following equation to determine time.  

vf = vi + a * t  

0 = 20.8 – 0.5 * t  

Solve for t = 41 seconds  

(c) the distance travels by it during the first and fifth second are.  

d = vi * t + ½ * a * t^2  

d1 = 20.8 * 1 – ½ * 0.5 * 1^2 = 20.55 m  

The easiest way to the distance for the 5th second is:

d = vi * t + ½ * a * t^2, a = -0.5  

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m  

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 =  106.8m

d6 – d5 = 15.3 m  

this is the required solution.


3 0
3 years ago
A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.69 m above the bottom of the chute with
Veseljchak [2.6K]

Answer:

x = 6.94 m

Explanation:

For this exercise we can find the speed at the bottom of the ramp using energy conservation

Starting point. Higher

            Em₀ = K + U = ½ m v₀² + m g h

Final point. Lower

            Em_{f} = K = ½ m v²

            Em₀ = Em_{f}

            ½ m v₀² + m g h = ½ m v²

            v² = v₀² + 2 g h

             

Let's calculate

             v = √(1.23² + 2 9.8 1.69)

             v = 5.89 m / s

In the horizontal part we can use the relationship between work and the variation of kinetic energy

            W = ΔK

            -fr x = 0- ½ m v²  

               

Newton's second law

              N- W = 0

     

The equation for the friction is

               fr = μ N

               fr = μ m g

We replace

             μ m g x = ½ m v²

             x = v² / 2μ g

Let's calculate

            x = 5.89² / (2 0.255 9.8)

            x = 6.94 m

6 0
4 years ago
Read 2 more answers
Which type of energy is associated with electric currents?
zalisa [80]
B. Electrical energy

 Among the choices given, the type of energy associated with electric currents is electrical energy. By its definition, electric current is the flow of charged particles through a conductor or a conduction medium, for example, a wire. Basically, it involves electricity. It is similar to water current but instead of water molecules, charged particles move down a conductor. These charged particles are mostly electrons which move freely and at random. When all the free electrons move in the same direction, a current is created.



8 0
3 years ago
Sonia was experimenting with electric charges. She tied two inflated balloons together, held them next to each other, and rubbed
lions [1.4K]

Answer: They will repel each other.

Explanation:

Two inflated balloons when rubbed with woolen cloth will lead to repeal each other because of the similar charges on both the balloons.

Rubbing both the balloons together by the woolen cloth will introduce negative charge in the balloons.

As, we know that the same charges repeal each other both of the balloons with be apart from each other.

This is due to the static electricity, the negatively charged particles jump to the positive one. When balloons are rubbed they become negatively charged.

3 0
4 years ago
Read 2 more answers
Other questions:
  • In a real machine, the work output is always less than the work input.<br><br> True<br> False
    7·2 answers
  • Which of the following statements is true? Group of answer choices The shortest wavelength of light is the visible light, which
    13·1 answer
  • Your friend has been given a laser for her birthday. Unfortunately, she did not receive a manual with it and so she doesn't know
    15·2 answers
  • A particle with unit charge ​(qequals​1) enters a constant magnetic field Bequals2iplus2j with velocity vequals22k. Find the mag
    5·1 answer
  • I really need help. I want a detailed solution
    11·1 answer
  • What are some examples of focus
    14·2 answers
  • Place the items in the correct order when they occur from 1 to 5.
    10·1 answer
  • ANSWER As Soon As Possible
    9·2 answers
  • Please solve this question ​
    7·2 answers
  • Question 25 of 25Two boxes are filled with air. The molecules that make up the air in Box Ahave more kinetic energy than those i
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!