All categories

3 years ago

A postal box has a side length of 15.2cm find the area of its base

Mathematics

2 answers:

snow_tiger [21]3 years ago

6 0

15.2 cm x 2

since, it is a box.

so, equals 30.4 cm^2

Hope it's right :)

Oliga [24]3 years ago

3 0

The area of the postal box base is 231.04 cm^2.

You might be interested in

Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap

gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

$\frac{dV}{dt}=15ft^3/min$

We have to find the increasing rate of change of height of pile when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r= $\frac{d}{2}=\frac{h}{2}$

Volume of pile= $\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3$

$\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}$

h=12 ft

Substitute the values

$15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}$

$\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}$

$\frac{dh}{dt}=0.13ft/min$

7 0

4 years ago

Jack is mowing a lawn that has a shed. needs to know area of lawn to mow. dimensions of yard are 5x by 13 x-4 . she'd are 2x by

Elena-2011 [213]

The diagram of the lawn and the shed is shown below.

The area of the lawn needed to be mowed equals to the area of the yard minus the area of the shed

The area of the yard = $(5x)(13x-4) = 65 x^{2} -20x$
The area of the shed = $(2x)(2x+4)=4 x^{2} +8x$

The area of the lawn = $65 x^{2} -20x-(4 x^{2} +8x)$
The area of the lawn = $65 x^{2} -20x-4 x^{2} -8x$
The area of the lawn = $61 x^{2} -28x$

5 0

3 years ago

If diana spends 25 minutes running at the gym how many minutes does she spend lifting weight

eimsori [14]

Answer:

Step-by-step explanation:

The question doesn’t say that she lifted weights

6 0

3 years ago

Read 2 more answers

How to factorise the difference of perfect squares. for the g on the top and j on the top

Fed [463]

Answer:

see explanation

Step-by-step explanation:

A difference of two squares is factored as

a² - b² = (a - b)(a + b)

(g)

1 - 81y²

= 1² - (9y)²

= (1 - 9y)(1 + 9y)

(j)

64x² - 25y²

= (8x)² - (5y)²

= (8x - 5y)(8x + 5y)

7 0

3 years ago

suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.

emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma( $\alpha ,\beta$ )