Question

The vertex form of the equation of a parabola is y=2(x+3)^2-5. What is the standard form of the equation?

Answer 1

To find the standard form of the equation, you need to:
1. Write the Equation Out:
$y = 2(x+3)^{2} -5$
2. Distribute the Exponent:
$y = 2( x^{2} +6x+9)-5$
3. Use the Distributive Property:
$y = 2 x^{2} +12x+18-5$
4. Combine Like Terms:
$y = 2 x^{2} +12x+13$

Your Answer: $y = 2 x^{2} +12x+13$
Hope this helps!