Answer:

Step-by-step explanation:
<u>Exponents Properties</u>
We need to recall the following properties of exponents:


We are given the expression:

We need to express the following expression in terms of n.

It's necessary to modify the expression to use the given equivalence.
Recall
. Thus:

Applying the property:

Substituting the given expression:

Or, equivalently:

<u>Answer:</u>
-348
<u>Step-by-step explanation:</u>
We are given the following arithmetic sequence and we are to find the sum of its first 12 terms:
1, -4, -9, -14, . . .
For that, we will use the formula for the sum of the arithmetic mean:

We know the value of the first term (
) but we need to find the value of
. So we will use the following formula:



Substituting these values in the sum formula to get:

-348
A. -3+4i Square both numbers, add them, then find the square root. Essentially, use the Pythagorean theorem. -3^2 + 4^2 9 + 16=25 Square root of 25 is 5.
The r-value, or common ratio, can be calculated by dividing any two consecutive terms in a geometric sequence.
The answer is no solutions