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shusha [124]
4 years ago
5

How many acetyl coa molecules may be obtained from oxidation of a 16-carbon fatty acid?

Chemistry
1 answer:
Aleksandr [31]4 years ago
3 0
The oxidation of a 16-carbon fatty acid produces 8 acetyl CoA molecules. A 16-carbon fatty acid is a palmitic acid. To determine the number of moles produced in the oxidation reaction, divide the number of carbon chains in the fatty acid by 2. 

16 moles / 2 = 8 moles CoA <span />
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A sample of neon gas occupies 105 L at 27°C under a pressure of
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Answer: Volume occupied by given neon sample at standard condition is 123.84 L.

Explanation:

Given: V_{1} = 105 L,    T_{1} = 27^{o}C = (27 + 273) K = 300 K,     P_{1} = 985 torr

At standard conditions,

T_{2} = 273 K,     P_{2} = 760 K,        V_{2} = ?

Formula used to calculate the volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{985 torr \times 105 L}{300 K} = \frac{760 torr \times V_{2}}{273 K}\\V_{2} = \frac{94116.75}{760} L\\= 123.84 L

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8 0
3 years ago
If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it? (Hint: Us
Studentka2010 [4]

Answer: We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.

Explanation:

According to the neutralization law,

M_1V_1=M_2V_2

where,

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V_2 = volume of resulting solution = ?

Now put all the given values in the above law, we get the volume of resulting solution.

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We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.

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In the given question, in BrF3, fluorine follows octet rule, while bromine does not follow the octet rule.  


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