Answer:
z = 8
Step-by-step explanation:
Solve for z:
(z + 4)/3 - 6 = (2 (5 - z))/3
Put each term in (z + 4)/3 - 6 over the common denominator 3: (z + 4)/3 - 6 = (z + 4)/3 - 18/3:
(z + 4)/3 - 18/3 = (2 (5 - z))/3
(z + 4)/3 - 18/3 = ((z + 4) - 18)/3:
(z - 18 + 4)/3 = (2 (5 - z))/3
Add like terms. 4 - 18 = -14:
(z - 14)/3 = (2 (5 - z))/3
Multiply both sides by 3:
(3 (z - 14))/3 = (3×2 (5 - z))/3
(3 (z - 14))/3 = 3/3×(z - 14) = z - 14:
z - 14 = (3×2 (5 - z))/3
(3×2 (5 - z))/3 = 3/3×2 (5 - z) = 2 (5 - z):
z - 14 = 2 (5 - z)
Expand out terms of the right hand side:
z - 14 = 10 - 2 z
Add 2 z to both sides:
2 z + z - 14 = (2 z - 2 z) + 10
2 z - 2 z = 0:
2 z + z - 14 = 10
z + 2 z = 3 z:
3 z - 14 = 10
Add 14 to both sides:
3 z + (14 - 14) = 14 + 10
14 - 14 = 0:
3 z = 10 + 14
10 + 14 = 24:
3 z = 24
Divide both sides of 3 z = 24 by 3:
(3 z)/3 = 24/3
3/3 = 1:
z = 24/3
The gcd of 24 and 3 is 3, so 24/3 = (3×8)/(3×1) = 3/3×8 = 8:
Answer: z = 8
Answer:
The time required to get a total amount of $ 640.00 from compound interest on a principal of $ 440.00 at an interest rate of 5.6% per year and compounded 365 times per year is approximately 7 years.
Step-by-step explanation:
Given
- Principle Amount P = $440
- Interest rate r = 5.6% = 0.056
To determine:
Time period t = ?
Using the formula

solving for t
t = ln(A/P) / n[ln(1 + r/n)]
substituting the values A = 640, P = 440, n = 365 and r = 0.056
t = ln(640/440) / ( 365 × [ln(1 + 0.00015342465753425/365)] )
t = 6.691
t ≈ 7 (nearest year)
Therefore, the time required to get a total amount of $ 640.00 from compound interest on a principal of $ 440.00 at an interest rate of 5.6% per year and compounded 365 times per year is approximately 7 years.
6 is the greatest common factor because that is the highest number they can both go into
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