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marusya05 [52]
3 years ago
5

What is the mean of this discrete random variable?

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0
My answer is 28.5 i believe i just added all of my numbers for the x variable and i divided it by by 6 because thats how many numbers you have
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3. Given this quadratic equation, 2x2 - x - 28 = 0,
JulijaS [17]

Answer:

a) (2x+7)(x-4)

b) x = -7/2 and x = 4

Step-by-step explanation:

a) (2x  ?)(x  ?)

set up the above and considered factors of 28 that, when paired with 2, would give me -1x and -28  → (1·28, 2·14, 4·7)

after trial-and-error, found that 4 and 7 worked (used un-FOIL)

b) 2x + 7 = 0

2x = -7

x = -7/2

*********

x-4 = 0

x = 4

4 0
2 years ago
The diameter of a planet is about 10,652 mi. The diameter of the planet's moon is about 25% of the planet. What percent of the v
alekssr [168]

Answer:

2\%

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x----> the volume of  the planet's moon

y---> the volume of the planet

so

z^{3}=\frac{x}{y}

In this problem we have

z=0.25

elevated to the cube

z^{3}=0.25^{3}=0.015625

Find the percent

0.015625*100=1.56\%

Round to the nearest whole number

1.56\%=2\%

5 0
3 years ago
The graph of a proportional relationship passes through (6, 48) and (1, y). Find y.
ser-zykov [4K]
The answer is 8.  this is because 6/1=6 so 48/6= 8
     

4 0
3 years ago
How do I find x?? It’s in french by the way.
DENIUS [597]

Answer:

The answer is 108

Step-by-step explanation:

The angle is obtuse and the only obtuse answer is 108.

5 0
3 years ago
Read 2 more answers
Find the permeter of a quadrilateral with vertices at C (2,4), D(1,1), E(5,0), and F(3,4). Round your answer to the nearest hund
denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\ c =  \sqrt{ {a}^{2} +  {b}^{2}  }

dc =  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\  cf = 1 \\ fe =  \sqrt{ {4}^{2}  +  {2}^{2} }  =  \sqrt{20}  \\ de =  \sqrt{ {1}^{2} +  {4}^{2}  }  =  \sqrt{17}  \\  \sqrt{10}  + 1 +  \sqrt{20}  +  \sqrt{17}  = 12.76

7 0
3 years ago
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