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3 years ago

Why are you allowed to move the decimal points before dividing with decimals? Explain your reasoning.

2 answers:

7 0

If you move the decimal point the same number of places in the dividend and the divisor, you are multiplying them both by the same power of 10. That does not change the quotient.

Goshia [24]3 years ago

6 0

Answer:

If you move the decimal point the same number of places in the dividend and the divisor, you are multiplying them both by the same power of 10. That does not change the quotient.

Step-by-step explanation:

it was what i got and it was right

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The length of a rectangle is 18 cm and its breadth is 11 cm. Find area of the rectangle.

zepelin [54]

Step-by-step explanation:

Area = length×breath

=18×11

=198cm²

4 0

2 years ago

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Line AB has endpoints A(3,4) and B(-2,8). What is AB to the nearest tenth

Nadya [2.5K]

Answer:

6.4

Step-by-step explanation:

To find the distance you have to do this formula.

$\sqrt{(x2 -x1)^{2}+(y2-y1)^{2}} \\\sqrt{(-2 -3)^{2} + (8-4)^{2}\\} \\\sqrt{(-5)^{2} + (4)^{2}} \\\sqrt{25 + 16} \\\sqrt{41} \\ \\\sqrt{41} = 6.40312\\6.4$

6.4 is the answer rounded to the nearest tenth.

Hope this helps!!

3 0

2 years ago

Find the range for the given data in 115, 534, 122, 599, 417, 289 A) 534 B) 167 C)115 D)484

Tamiku [17]

The answer is 484.Or D.

4 0

3 years ago

Read 2 more answers

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

In a survey of students at a local high school, 30% of the students said they liked tater tots and 15% of the students said they

Artemon [7]

Based on the given problem above, the proportion of the students responding to the survey that said that they liked at least one of the two side dishes is 3/10. Because<span> 30% said they like tater tots and all the ones who said they liked fries are the same people then you're only looking at the 30% wherein 30/100 is 3/10 which makes 3/10 the right answer.</span>

4 0

3 years ago

Read 2 more answers